A fish swimming in a horizontal plane has velocity i = (4.00 î + 1.00 ĵ) m/s at a point in the ocean where the position relative to a certain rock is i = (16.0 î − 3.20 ĵ) m. After the fish swims with constant acceleration for 15.0 s, its velocity is  = (21.0 î − 6.00 ĵ) m/s.   In what direction is it moving?     ______________?       ° counterclockwise from the +x-axis

Principles of Physics: A Calculus-Based Text
5th Edition
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter2: Motion In One Dimension
Section: Chapter Questions
Problem 11P: A particle moves along the x axis according to the equation x = 2.00 + 3.00t 1.00t2, where x is in...
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A fish swimming in a horizontal plane has velocity i = (4.00 î + 1.00 ĵ) m/s at a point in the ocean where the position relative to a certain rock is i = (16.0 î − 3.20 ĵ) m. After the fish swims with constant acceleration for 15.0 s, its velocity is  = (21.0 î − 6.00 ĵ) m/s.

 

In what direction is it moving?
    ______________?       ° counterclockwise from the +x-axis

Expert Solution
Step 1

Acceleration of the fish is

v=u+ata=v-ut=21i^-6j^m/s-4i^+1j^m/s15s=17i^-7j^m/s15s=1.13i^-0.466j^m/s2

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