(a) Find Vs in the network in the figure below if V, = 4/0°V. 1 Ω -j1 Ω HH 1Ω + V Σ2Ω + = -j1 Ω ΖΩ

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1. For the circuit shown below, use the current divider rule to find the phasors 13 and Vo in polar form: answer: 13 = 7.694 65.3° A, V₁ =¹46.161 Z-24.7° V 1₁ = 940° A ↑ R₁ 15 02 L₁ j8n A₂ www. 4Ω 13↓ с -j6n Hii + V₂ R3 ΖΩ L₂ j5Ω

Find the voltages in their rectangular form (Solve by node method) -j5 N 1/0° A ( 2 + j4 N 4 - j2 N *) 0.5/-90° A Ref. (b)