(a) Find the useful power output (in W) of an elevator motor that lifts a 2600 kg load a height of 30.0 m in 12.0 s, if it also increases the speed from rest to 4.00 m/s. Note that the total mass of the counterbalanced system is 10,000 kg-so that only 2600 kg is raised in height, but the full 10,000 kg is accelerated. (Enter a number.) 250.000 X W (b) What does 0.625 t cost (in cents), if electricity is $0.0900 per kW h? (Enter a number.) x cents

(a) Find the useful power output (in W) of an elevator motor that lifts a 2600 kg load a height of 30.0 m in 12.0 s, if it also increases the speed from rest to 4.00 m/s. Note that the total mass of the counterbalanced system is 10,000 kg-so that only 2600 kg is raised in height, but the full 10,000 kg is accelerated. (Enter a number.) 250.000 X W (b) What does 0.625 t cost (in cents), if electricity is $0.0900 per kW h? (Enter a number.) x cents

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Description: (a) Find the useful power output (in W) of an elevator motor that lifts a 2600 kg load a height of 30.0 m in 12.0 s, if it also increases the speed from rest to 4.00 m/s. Note that the total mass of thecounterbalanced system is 10,000 kg-so that onl

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ISBN:9781305952300

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Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

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(a) Find the useful power output (in W) of an elevator motor that lifts a 2600 kg load a height of 30.0 m in 12.0 s, if it also increases the speed from rest to 4.00 m/s. Note that the total mass of the
counterbalanced system is 10,000 kg-so that only 2600 kg is raised in height, but the full 10,000 kg is accelerated. (Enter a number.)
250.000
X W
(b) What does it cost (in cents), if electricity is $0.0900 per kWh? (Enter a number.)
0.625
X cents
+

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