(a) Find the useful power output (in W) of an elevator motor that lifts a 2600 kg load a height of 30.0 m in 12.0 s, if it also increases the speed from rest to 4.00 m/s. Note that the total mass of the counterbalanced system is 10,000 kg-so that only 2600 kg is raised in height, but the full 10,000 kg is accelerated. (Enter a number.) 250.000 X W (b) What does 0.625 t cost (in cents), if electricity is $0.0900 per kW h? (Enter a number.) x cents

(a) Find the useful power output (in W) of an elevator motor that lifts a 2600 kg load a height of 30.0 m in 12.0 s, if it also increases the speed from rest to 4.00 m/s. Note that the total mass of the counterbalanced system is 10,000 kg-so that only 2600 kg is raised in height, but the full 10,000 kg is accelerated. (Enter a number.) 250.000 X W (b) What does 0.625 t cost (in cents), if electricity is $0.0900 per kW h? (Enter a number.) x cents

Name: (a) Find the useful power output (in W) of an elevator motor that lif
Uploaded: 2024-03-20T06:57:25.000Z
Channel: Bartleby
Description: (a) Find the useful power output (in W) of an elevator motor that lifts a 2600 kg load a height of 30.0 m in 12.0 s, if it also increases the speed from rest to 4.00 m/s. Note that the total mass of thecounterbalanced system is 10,000 kg-so that onl

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Similar questions

A 620-kg elevator starts from rest and moves upward for 4.50 s with constant acceleration until it reaches its cruising speed, 1.74 m/s. (a) What is the average power of the elevator motor during this period? (b) How does this amount of power compare with its power during an upward trip with constant speed? (Give the power during an upward trip with constant speed.)
(a) Find the useful power output (in W) of an elevator motor that lifts a 2600 kg load a height of 30.0 m in 12.0 s, if it also increases the speed from rest to 4.00 m/s. Note that the total mass of the counterbalanced system is 10,000 kg-so that only 2600 kg is raised in height, but the full 10,000 kg is accelerated. (Enter a number.) X W 72100 (b) What does it cost (in cents), if electricity is $0.0900 per kW h? (Enter a number.) 2.163 X cents
(a) Find the useful power output (in W) of an elevator motor that lifts a 2200 kg load a height of 30.0 m in 12.0 s, if it also increases the speed from rest to 4.00 m/s. Note that the total mass of the counterbalanced system is 10,000 kg-so that only 2200 kg is raised in height, but the full 10,000 kg is accelerated. W (b) What does it cost (in cents), if electricity is $0.0900 per kW.h? cents
A lift motor has to move a fully laden lift 4.59 m between floor 1 and floor 2. The lift has a mass of 2150kg and takes 2.41 s to move from floor 1 to floor 2 (ignore friction). What is the power of the lift in watts during this time? (Assume that acceleration due to gravity is 9.81 m/s²; round your answer to two decimal places; DO NOT include units)
An elevator motor lifts a 2750-kg load to a height of 37m in 12.5s. Find the useful power output of the elevator motor, if it also increases the speed from rest to 3.95 m/s. Assume that the total mass of the counterbalanced system is 10,000 kg — so that only 2750 kg is raised in height, but the full 10,000 kg is accelerated. How much does it cost, in dollars per hour, if the electricity cost is $0.075 per kW⋅h?
Cathy just rebuilt the engine in her car (mcar = 1,200 kg) and the rebuilt engine can supply 72,900 W of power, if all the power from the engine goes into moving the car, how much time would it take Cathy’s car to go from 0 to 27 m/s on a flat, horizontal road?
Solve it correctly please. I will rate accordingly
answer botth...no handwritten
(a) Find the useful power output of an elevator motor that lifts a 350000-g load a height of 450 cm in 12.0 s, if it also increases the speed from rest to 5.00 m/s. Note that the total mass of the counterbalanced system is 20000 kg-so that only 350000 kg is raised in height, but the full 20000 kg is accelerated. (b) What does it cost, if electricity is $0.0900 per kW · h ?
Calculate the average power outp
6-8
(a) Find the useful power output (in W) of an elevator motor that lifts a 2400 kg load a height of 30.0 m in 12.0 s, if it also increases the speed from rest to 4.00 m/s. Note that the total mass of the counterbalanced system is 10,000 kg-so that only 2400 kg is raised in height, but the full 10,000 kg is accelerated. (Enter a number.) W (b) What does it cost (in cents), if electricity is $0.0900 per kW h? (Enter a number.) cents