A FIELD SOIL has a relative density of 75% and the following data:emax = 1.3emin = 0.4Specific gravity of solids = 2.68Degree of stauration = 68%For the sample:Calculate the voids ratio and moisture content of the field soilCalculate the dry density of the field soilCalculate the throretical maximum (zero air void) dry density at a water content of 18%

Given Relative density of 75% emax = 1.3 emin = 0.4 Specific gravity of solids = 2.68 Degree of stauration = 68%Calculating the voids ratio and moisture content of the field soil Relative density is given byRelative density = emax-eemax-eminPutting values0.75 =1.3-e1.3-0.4e = 0.625For soil we have expressionwG=eSHere w is moisture content, G is specofic gravity,e is void ratio, S is degree of saturationPutting valuesw×2.68=0.625×0.68w = 0.158Therefore void ratio and moisture content of field soil is 0.625 and 15.8 %Calculating the dry density of the field soil To find out dry density first find bulk unit wtBulk unit wt =unit wt of water×G+es1+eBulk unit wt =1000×2.68+0.625×0.681+0.625Bulk unit wt =1910kg/m3Dry density = Bulk unit wt1+wDry density = 19101+0.158Dry density =1650.06 kg/m3Calculating the theoretical maximum (zero air void) dry density at a water content of 18% Max dry density when air voids are zeroMax dry density =Density of water×G1-na1+wGPuttimg valuesMax dry density =1000×2.681-01+0.18×2.68Max dry density =1807 kg/m3

Answered: A FIELD SOIL has a relative density of…

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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A FIELD SOIL has a relative density of 75% and the following data:

e_max = 1.3
e_min = 0.4
Specific gravity of solids = 2.68
Degree of stauration = 68%

For the sample:

Calculate the voids ratio and moisture content of the field soil
Calculate the dry density of the field soil
Calculate the throretical maximum (zero air void) dry density at a water content of 18%

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