A fence is required around a field is shaped as shown below. It consists of a rectangle of length L and width W and a right triangle that is symmetrical about the central horizontal axis of the rectangle. Suppose the width is known (in metres), and the enclosed area A is known (in square metres). L D W 1. Use pen and paper to determine the equations for the total area and perimeter in terms of the width W, and length L. 2. Use MATLAB to plot the perimeter against the width as a black solid line, assuming the width to be between 7 to 20 metres and the area to be 111 m2. 3. Use the min() function to determine the minimum perimeter required to fence off the 111 m2 area. Print the corresponding length and width required, and mark the minimum point on the previous plot with a blue diamond. 5.1) Referring to Task 5 Part 3, what is the minimum perimeter required to fence the area of 111 m^2? Round up your answer to two decimal. A. 41.23 metres O B. 50.87 metres C. 46.30 metres O D. 54.06 metres 5.2) Determine the index of the matrices which result in the minimum perimeter in Question 5.1. * O A. 174 O B.260 O C. 378 O D. 107 5.3) What is the corresponding length for the minimum perimeter? Round up your answer to two decimal places. * O A. 6.78 metre O B. 7.61 metre O C. 10.53 metre O D. 13.27 metre 5.4) Next, what is the corresponding width for the minimum perimeter?* A. 8.06 metre OB. 8.73 metre O C. 9.59 metre O D. 10.77 metre 5.5) Which of the following code can be used for solving Task 5? O A. [min_perimeter, ID] = min(perimeter) B. length = (A - (0.25*(w.^2)*sind(45))). *w O C. perimeter = (A - (0.25*(W.^2) *cosd(45)))./w O D. All of the above
A fence is required around a field is shaped as shown below. It consists of a rectangle of length L and width W and a right triangle that is symmetrical about the central horizontal axis of the rectangle. Suppose the width is known (in metres), and the enclosed area A is known (in square metres). L D W 1. Use pen and paper to determine the equations for the total area and perimeter in terms of the width W, and length L. 2. Use MATLAB to plot the perimeter against the width as a black solid line, assuming the width to be between 7 to 20 metres and the area to be 111 m2. 3. Use the min() function to determine the minimum perimeter required to fence off the 111 m2 area. Print the corresponding length and width required, and mark the minimum point on the previous plot with a blue diamond. 5.1) Referring to Task 5 Part 3, what is the minimum perimeter required to fence the area of 111 m^2? Round up your answer to two decimal. A. 41.23 metres O B. 50.87 metres C. 46.30 metres O D. 54.06 metres 5.2) Determine the index of the matrices which result in the minimum perimeter in Question 5.1. * O A. 174 O B.260 O C. 378 O D. 107 5.3) What is the corresponding length for the minimum perimeter? Round up your answer to two decimal places. * O A. 6.78 metre O B. 7.61 metre O C. 10.53 metre O D. 13.27 metre 5.4) Next, what is the corresponding width for the minimum perimeter?* A. 8.06 metre OB. 8.73 metre O C. 9.59 metre O D. 10.77 metre 5.5) Which of the following code can be used for solving Task 5? O A. [min_perimeter, ID] = min(perimeter) B. length = (A - (0.25*(w.^2)*sind(45))). *w O C. perimeter = (A - (0.25*(W.^2) *cosd(45)))./w O D. All of the above
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