A fancart of mass 0.8 kg initially has a velocity of < 0.7, 0, 0 > m/s. Then the fan is turned on, and the air exerts a constant force of < −0.3, 0, 0 > N on the cart for 1.5 seconds. What is the change in momentum of the fancart over this 1.5 second interval? What is the change in kinetic energy of the fancart over this 1.5 second interval?

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A: Mass of the jeepney is m = 1500 kg Velocity of the jeepney is v = 15 m/s

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A: SOlution:

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A:

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A: Solution attached in the photo

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Q: A golf ball of mass 50 grams is struck and has a velocity of 70 m/s when it leaves the tee.  The…

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Q: 1. A cardinal (Richmondena cardinalis) of mass 3.70×10−2 kg and a baseball of mass 0.146 kg have the…

A: According to guidelines we need to solve only first question kindly repost other questions in the…

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A: Determine the total linear momentum.

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A: This problem can be solved using the formula for kinematics equation of motion and impulse.

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A: pball=pbulletmballvball=mbulletvbullet       vball=mbulletvbulletmball             =2.96 g10-3…

Q: Calculate the momentum of a particle, mass (1.00x10^0) kg, moving at a velocity of (6.0x10^1) j…

A: mass of particle = 1 kg velocity of particle = 60 j^ kmsec= 60000 j^ ms

Q: A 200-g bullet, initially travelling at 400 m/s, collides with a 1.50 kg block that sits on the edge…

A: Since you have asked multiple subparts I have answered first 3 subparts, if you need answers of…

Q: Question 6 The kinetic energy of 50-kg runner is 250 J. What is the momentum of the runner? A 0.2 kg…

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A: As per our guidelines, we are supposed to answer only first three subparts in case of multiple…

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A:

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A: given -            mass of truck =2180 kg              Vi = 33 km/h              Vf = 58 km/h

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A: Since there are multiple questions, we answer the first three questions.If you need answer of any…