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- The Air on 1 ATM on T. 250 K And the free flow rate is 30 meters It flows across a diameter cylinder 2,5 cm The cylinder 'surface is guarded on temperature 350 k, count : *) The rate of heat transfer is 1 meter long Cylinder >The TPD method measures temperature elevations in a tissue region during a heating pulse and its later temperature decay after the pulse. It is then using the Pennes bioheat equation to perform a curve fitting to determine the local blood perfusion rate. If the TPD probe is placed in the vicinity of very large blood vessel, will the TPD technique provide an accurate measurement of the local blood perfusion in the vicinity of this large blood vessel? Explain briefly. (Hint: Is the Pennes bioheat equation accurate surrounding a large blood vessel?)Subject : Heat Transfer Solve the surface temperature using the parameters: h steam = 17.6319 W/m2 Kh air = 25 W/m2 KT steam = 120 deg CT air = 30 deg C k of cooling fill= 0.147 W/(m.K) Area of fill = 128.64 m'2 thickness of cooling = 2m
- Heat Transfer question In order to cool down a hot steel sphere (its diameter is 5 cm), CO2 gas is blown over it through a pipe with a diameter of 10 cm. The CO2 gas is kept at atmospheric pressure while moving through a smooth pipe at a speed of 6 m/sec. The gas temperature entering the pipe is 300K and exiting the pipe is 340 K. The pipe temperature at the entrance is 350K and at the exit is 550K. The sphere is located just about the pipe exit. Find the convective heat transfer coefficient of the gas moving in the pipe, the heat transfer rate at the pipe and the pipe length. What is the surface temperature of the sphere if the heat transfer rate between the sphere and the gas is 7W and its surface temperature is higher than the gas?3.9 The heat transfer coefficients for the flow of 26.6°C air over a sphere of 1.25 cm in diameter are measured by observing the temperature-time history of a copper ball the same dimension. The temperature of the copper ball was measured by two thermocouples, one located in the center and the other near the surface. The two thermocouples registered, within the accuracy of the recording instruments, the same temperature at any given instant. In one test run, the initial temperature of the ball was 66°C, and the temperature decreased by 7°C in 1.15 min. Calculate the heat transfer coefficient for this case.THIS SUBJECT IS DYNAMICSSHOW COMPLETE AND CLEAR SOLUTION
- The thermal boundary layer in heat transfer exists whenever there is a difference between the temperatures of the fluid and the outside environment. For fluid flow, how does a boundary layer form?A. Because common surfaces are not smooth, the flow is hindered, and boundary layers are formed.B. The disturbances on the streamlines in high Reynolds number flow produces boundary layer.C. The existence of walls or “boundaries” that keep the fluid inside (or outside) creates the boundary layer.D. Velocity profiles are inherently approaching no-slip condition because of the resistance of the walls.QIt is required to air condition a factory building (27mx 18mx4m). The 27m wall is type B and faces south. The following data is available: Two glass windows in south wall 3mx 1.5m each with internal shade, lighting load is 20 Watt fluorescent per m² floor area. The inside air conditions are: 24°C DBT and 50% RH. The outside air conditions are: 40°C DBT, DR-18.0°C and 30°C WBT. Other related data are: Uwall=1.4 W/m² K, Uglass 3.5 W/m² K, Scglass=0.7, occupancy=8 persons doing light bench work and CLF occupancy 0.85. The building is of heavy construction with light color located at 40°N. Calculate the building cooling load from the South wall, windows, lighting and occupancy on August at 4:00 p.m. الاتحادThe Air on 1st atmosphere on T = 250 K And the free flow rate is 30 meters It flows across a diameter cylinder 2,5 cm The cylinder 'surface is guarded on temperature 350 k.count : coefficient heat transfers.
- QIt is required to air condition a factory building (27mx 18mx4m). The 27m wall is type B and faces south. The following data is available: Two glass windows in south wall 3mx 1.5m each with internal shade, lighting load is 20 Watt fluorescent per m² floor area. The inside air conditions are: 24°C DBT and 50% RH. The outside air conditions are: 40°C DBT, DR-18.0°C and 30° WBT. Other related data are: Uwall-1.4 W/m² K, Uglass-3.5 W/m² K, Scglass-0.7, occupancy-8 persons doing light bench work and CLF occupancy=0.85. The building is of heavy construction with light color located at 40°N. Calculate the building cooling load from the South wall, windows, lighting and occupancy on August at 4:00 p.m.NUMBER 4 A food product wants to be produced in a small round shape (pellet) by freezing it in a water blast freezer freezer. Air freezer operates at -30 ° C. The initial product temperature is 25 ° C. The pellet has a diameter of 1.2 cm, and a density of 980 kg / m³. The initial freezing temperature is -2.5 ° C. The latent heat of freezing of the product is 280 kJ / kg. The thermal conductivity of the frozen product is 1.9 W / (m ° C). The convective heat transfer coefficient is 50 W / (m² K). Calculate the freeze time. t f = hourSpecific Heat, Cp Water Thermal Thermal Content, Temperature, T Density, p Conductivity, k Ibm/ft3 Diffusivity, a ft2/s Food %(mass) °F Btu/h-ft.°F Btu/lbm-R Fruits/Vegetables Apple juice Apples Apples, dried Apricots, dried Bananas, fresh 1.51 x 10-6 1.47 x 10-6 87 68 62.4 0.323 0.922 85 32-86 52.4 0.242 0.910 41.6 73 53.4 0.127 1.03 x 10-6 0.650 1.22 x 10-6 1.51 × 10-6 43.6 73 82.4 0.217 0.662 76 41 61.2 0.278 0.856 Broccoli 21 35.0 0.223 | 1.42 x 10-6 Cherries, fresh Figs Grape juice 92 32-86 65.5 0.315 0.952 40.4 73 77.5 0.179 1.03 x 10-6 0.642 1.51 × 10-6 1.51 × 10-6 89 68 62.4 0.328 0.934 Peaches 36-90 2-32 59.9 0.304 0.934 Plums 3 38.1 0.143 | Potatoes 32-158 0-70 65.7 0.288 1.40 x 10-6 0.868 Raisins 32 73 86.2 0.217 1.18 x 10-6 0.592 Meats Beef, ground Beef, lean 67 43 59.3 0.235 1.40 x 10-6 0.802 74 37 68.0 0.272 1.40 x 10-6 0.844 Beef fat 95 50.5 0.110 72 95 73 Beef liver 0.259 0.832 1.18 x 10-6 1.40 x 10-6 Cat food 39.7 71.2 0.188 0.638 Chicken breast 75 32 65.5 0.275 0.850