question in picture and characterize particles,) and mass spectrometers (to identify ions) all rely on this circular motionof charged particles in a magnetic field.At CERN, protons move almost the speed of light in a circle whose radius is over 4 km. In thisproblem we will figure out the magnetic field needed to bend them into this circle. I will walk youthrough the analysis. (The text also goes over a similar example in section 26.3)(a) Draw a diagram of a proton moving in the page, and the B field pointing perpendicular to it (inor out of the page.) Use the right hand rule to decide which way the force points and add theforce vector to your diagram.(b) Write the magnitude of the force in terms of q, v and B.(c) Recall that a force perpendicular to the motion will result in uniform circular motion withcentripetal acceleration ac = v² /r. Use this, the expression for the magnetic force that youalready wrote, and the second law (F=ma) to solve for the magnetic field, in Tesla, that isneeded – if we ignore relativity - to get a radiusr =speed of light) for a proton (mass 1.67 x 10-27 kg and charge 1.6 x 10-19 C.)4 km and speed v equal to c= 3X10$ (the(d) This should look ridiculously small. Why not make the field larger (CERN uses giant multi-Teslamagnets!) and the radius smaller? The answer is relativity. Without getting into the details,the error is that at speeds near c, the effective mass is almost all energy! To account for this,simply replace the kinetic energy we used earlier mv? with the relativistic energy, which isabout 7 TeV (= 71012 eV. ) Convert the energy to SI (J) units, noting that J=(charge e)(energyin eV.)Notice that the expression mv? shows up in our analysis via the net force so you can actuallycontinue to work either in eV or use the converted energy in J. Either way, be careful of units!Revise the analysis to include this correction and recalculate the needed B field. It should nowbe several Tesla, which explains the ever growing size of the CERN accelerator rings. A magnetic field turns the velocity of a particle but does not change the speed, because the force isalways perpendicular to the velocity. Particle accelerators (like CERN,) bubble chambers (to detect

Hello. Since your question has multiple sub-parts, we will solve the first three sub-parts for you.…

(a) Draw a diagram of a proton moving in the page, and the B field pointing perpendicular to it (in or out of the page.) Use the right hand rule to decide which way the force points and add the force vector to your diagram. (b) Write the magnitude of the force in terms of q, v and B. (c) Recall that a force perpendicular to the motion will result in uniform circular motion with centripetal acceleration ac = v² /r. Use this, the expression for the magnetic force that you already wrote, and the second law (F=ma) to solve for the magnetic field, in Tesla, that is needed – if we ignore relativity - to get a radius r = 4 km and speed v equal to c= 3X10$ (the speed of light) for a proton (mass 1.67 x 10-27 kg and charge 1.6 x 10-19 C.) %3D