A drained triaxial test on the normally consolidated clay showed that the failure plane makes an angle of 58 with the horizontal. If the sample was tested with a chamber confining pressure of 103.5KPA, what was the major principal stress at failure? (Unit in kPa) (Answer only number(whole number without unit) *

A drained triaxial test on the normally consolidated clay showed that the failure plane makes an angle of 58 with the horizontal. If the sample was tested with a chamber confining pressure of 103.5KPA, what was the major principal stress at failure? (Unit in kPa) (Answer only number(whole number without unit) *

Fundamentals of Geotechnical Engineering (MindTap Course List)

5th Edition

ISBN:9781305635180

Author:Braja M. Das, Nagaratnam Sivakugan

Publisher:Braja M. Das, Nagaratnam Sivakugan

Chapter10: Shear Strength Of Soil

Section: Chapter Questions

Problem 10.20P

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A drained triaxial test on the normally consolidated clay showed that the
failure plane makes an angle of 58 with the horizontal. If the sample was
tested with a chamber confining pressure of 103.5KPA, what was the
major principal stress at failure? (Unit in kPa) (Answer only number(whole
number without unit)
*
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Shear Stress 1. Please provide proper discussion and illustration. Clear and complete solution please thank you.
d) An oedometer test was also performed on a (saturated) reconstituted sample obtained at the site. The initial void ratio was calculated as 1.005 and the initial sample height was 20 mm. The following measurements were reported for each of the 24-hr stress increments: Table 4. Oedometer test measurements Normal stress (kPa) 1.5 13 26 52 104 208 416 Change in sample height (mm) 0.419 0.199 0.229 0.209 0.208 0.199 Plot the evolution of the void ratio resulting from the data above using semi-logarithmic axes (i.e. produce an e-log o'y plot). Is there anything you can comment on the stress history and consolidation state of the soil?
4.15 The following results were obtained from a liquid limit test on a clay using the Casagrande cup device. Number of blows 6 12 20 28 32 Water content (%) 52.5 47.1 43.2 38.6 37.0 (а) Determine the liquid limit of this clay. (b) If the natural water content is 38% and the plastic limit is 23%, calculate the liquidity index. (c) Do you expect a brittle type of failure for this soil? Justify your answer.
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A drained triaxial test on the normally consolidated clay showed that the failure plane makes an angle of 58 with the horizontal. If the sample was tested with a chamber confining pressure of 103.5kPA, what was the major principal stress at failure? (Unit in kPa) (Answer only number(whole number without unit)
A consolidated-undrained tri-axial test was conducted on a normally conslidated clay sample and the results are follows: Chamber confining pressure= 119kpa Deviator Stress at failure=90 kpa Pore water pressure= 58kpa These results were used to determine the drained friction angle of the soil. Compute the deviator stress (kpa) at failure when the drained test was conducted with the chamber confining pressure changed to 156 kpa. Use stored value. Answer to 5 decimal places.
6 A consolidated-undrained test was conducted on a normally consolidated clay sample. The results are as follows: Undrained angle of friction = 36.90°, Drained angle of friction = 67.62°, Deviator stress at failure = 573 lb/ft^2. Determine the pore water stress at failure in lb/ft^2. Round off to three decimal places.
Please give me right solution according to the question. In a triaxial test on a saturated clay, the sample was consolidated under a cell pressure of 160 kPa. After consolidation the cell pressure was increased to 350 kPa, and the sample was then failed under undrained condition. If the shear strength parameters of the soil are c’ = 15.2 kPa, ϕ’ = 26°, B = 1, Af = 0.27, determine the pore pressure at the failure.
9. A consolidated drained test was carried out on a sandy clay under a cell pressure of 250 kPa. A constant back pressure of 120 kPa applied throughout the test. The dimensions of the sample were 76 mm x 38 mm. Addional test data recorded at failure were: Load transducer force = 368 N 3 Measured change in volume = 2.42 x 10 m³ Axial deformation = 2.05 mm Determine the major principal stress, o, at failure. (455 kPa)
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During an oedometer test on a specimen of saturated clay, the thickness of the specimen decreased from 19.931 mm to 19.720 mm under an increment of stress from 200 to 400 kPa which was maintained for 24 hours. The stress was then removed from the specimen, its thickness was measured as 19.842 mm, and its water content determined as 26.8%. Taking Gs of the particles to be 2.70, calculate the void ratio before and after the application of the stress increment, and the coefficient of volume decrease (m,) for this stress range. (Ans: e,= 0.731, ez= 0.713, m, = 0.052 m²/MN)