A double-convex lens has a focal length of 6.00cm. (a) How far away from an insect 2.00mm long should the lens be held in order to produce an upright image 5.00mm long? (b) What is the image distance? A. p = +3.6 cm and q = -9 cm B. p = +3.6 cm and q = +9 cm C. p = -3.6 cm and q = -9 cm D. p = -3.6 cm and q = +9 cm

a converging lens has a focal length of 4.5cm. it forms an inverted image with an image distance of 5.5cm what is the magnification?

An eyeglass prescription that specifies a power of -1.0 diopters is describing a lens that has a focal length of O a. + 1 meter O b.- 100 cm O C. - 1 meter O d. - 1 cm An object placed 25 cm to the left of a +20 cm focal length lens produces a real image 100 cm to the right of the lens. What is the magnification? O a. - 4 Ob. - 0.25 O C. + 2 O d. - 1

A diverging lens has a focal length of -21.8cm. The image formed has a magnification of 0.54. What's the object distance? Answer in cm

= 3. A 15 cm tall object sits 80 cm to the left of a converging lens with a focal length of fi 30 cm. There is a second converging lens with a focal length of f2 = 20 cm sitting 60 cm to the right of the first converging lens. dige de a. Where is the image from the first lens formed? (find di1) f₁ = 30 cm do = 80cm di = ? C. -14 1-do₂ 'वे di = [130 - 50 ] = 48 cm to the right of lens 1 = b. What is the object distance for the second lens? (find doz) f₂ =20 cm do=48 cm di = ? Where is the final image formed? (find diz) do d. What is the distance between the original object and the final image? What is the overall magnification for this two-lens system? f. What is the height of the final image? (find hi2) 2

2. A convex (converging) lens produces a real, inverted image of an object that is magnified 2.50 times when the object is 19.0 cm from the lens. What is the focal length of the lens? cm

Example 2: What is the image distance when a pencil is placed 29.7 cm from a diverging lens of focal length f = -9.9 cm. q743 cm. M 0 25 The image is (real / virtual) The image is (upright / inverted) The image distance is The Magnification, M =