A doctor uses a 17.5 cm focal length magnifying glass to examine a suspected skin lesion on a patient. The magnifying glass is held a distance 12.0 cm from the lesion.   (a)Calculate the position of the image of the lesion (in cm). (Include the sign of the value in your answer.)  cm   (b) Calculation the magnification of the image of the lesion. (Include the sign of the value in your answer.   (c)Calculate the height of the image of the lesion (in mm). The measured height of the lesion is 1.95 mm. mm   (d) Describe the image Inverted and smaller than the object. Inverted and larger than the object.     Upright and smaller than the object. Upright and larger than the object. (e) Determine the position of the image relative to the lens  The image is on the same side of the lens as the lesion. The image is on the opposite side of the lens as the lesion.     The image is exactly at the position of the lens. It is impossible to tell where the position of the image is relative to the lens.

A dental hygienist uses a small concave mirror to look at the back of a patient's tooth. If the mirror is 1.64 cm from the tooth and the magnification is 1.80, what is the mirror's focal length? (Include the sign of the value in your answer.) cm

An individual is nearsighted; his near point is 11.0 cm and his far point is 51.0 cm. (a) What lens power is needed to correct his nearsightedness? 1.96 X The response you submitted has the wrong sign. diopters (b) When the lenses are in use, what is this person's near point? 11 X Your response differs from the correct answer by more than 10%. Double check your calculations. cm

A student with normal sight is surprised to see a possum scampering up the rear wall in the Lyle theatre. The possum is 30.0 cm long and the wall is 2.3 m away. The student's eyeballs have a diameter of 2.4 cm. How big is the image of the possum on the student's retina? (Units: cm)

A convex mirror has a focal length of magnitude 8.85 cm. (a) If the image is virtual, what is the object location for which the magnitude of the image distance is one third the magnitude of the object distance? (Enter distance in cm from the front of the mirror. If the image is real, enter NONE.) 11.8 Your response differs from the correct answer by more than 10%. Double check your calculations. cm (b) Find the magnification of the image. 0.33 State whether it is upright or inverted. upright inverted

When an object is placed 40.5 cm in front of a convex spherical mirror, a virtual image forms 12.0 cm behind the mirror. Determine the mirror's focal length in cm and the magnification. HINT (a) the mirror's focal length in cm cm (b) the magnification

Two converging lenses create an image 1.50 m away from the obiect. The first lens is placed 30 cm in front of the object. The first lens has a focus length of 20 cm and the second has a focus length of 15 cm. How far apart are the lenses be (x=?)? Drawing not to scale. X=? 30 cm 1.5 m

A typical human eye is nearly spherical, and is usually about 2.5 cm in diameter. Suppose a person first looks at a coin that is 2.4 cm in diameter and located 34.0 cm from her eye. Then, she looks up at a friend who is 1.8 m tall and 4.00 m away. Find the magnitude of the approximate size of each image (coin ℎI,coin and friend ℎI,friend) on her retina. (Hint: Just consider rays from the top and bottom of the object that pass through the center of the lens.) b) Are the images on her retina upright/inverted and/or virtual/real?

An object located 1.17 cm in front of a spherical mirror forms an image located 11.3 cm behind the mirror. (a) What is the mirror's radius of curvature (in cm)? cm (b) What is the magnification of the image?