A direct-mapped cache consists of 8 blocks. A byte-addressable main memory contains 4K blocks of eight bytes each. Access time for the cache is 20 ns and the time required to fill a cache slot from main memory is 300 ns. Assume a request is always started in sequential to cache and then to main memory. If a block is missing from cache, the entire block is brought into the cache and the access is restarted. Initially, the cache is empty. c) Compute the effective access time for this program. Show me how to solve using this equation: EAT = H x AccessC + (1 – H) x AccessMM where H is the cache hit rate and AccessC and AccessMM are the access times for cache and main memory, respectively. thanks
A direct-mapped cache consists of 8 blocks. A byte-addressable main memory contains 4K blocks of eight bytes each. Access time for the cache is 20 ns and the time required to fill a cache slot from main memory is 300 ns. Assume a request is always started in sequential to cache and then to main memory. If a block is missing from cache, the entire block is brought into the cache and the access is restarted. Initially, the cache is empty. c) Compute the effective access time for this program. Show me how to solve using this equation: EAT = H x AccessC + (1 – H) x AccessMM where H is the cache hit rate and AccessC and AccessMM are the access times for cache and main memory, respectively. thanks
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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A direct-mapped cache consists of 8 blocks. A byte-addressable main memory contains 4K blocks of eight bytes each. Access time for the cache is 20 ns and the time required to fill a cache slot from main memory is 300 ns. Assume a request is always started in sequential to cache and then to main memory. If a block is missing from cache, the entire block is brought into the cache and the access is restarted. Initially, the cache is empty.
c) Compute the effective access time for this program.
Show me how to solve using this equation:
EAT = H x AccessC + (1 – H) x AccessMM
where H is the cache hit rate and AccessC and AccessMM are the access times for cache and main memory, respectively.
thanks
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