3) A soccer player kicks a ball at an angle of 37° above the horizontal as shown above.= 10m/s²Goalpost25 m/s7.3m40mSin 37° = 0.60Cos 37° = 0.80a) Determine the horizontal and vertical component of the ball's velocity at thestarting point.b) Determine the maximum height.c) Determine the time it takes the ball to reach the goalpost.d) Determine the height of the ball when it reaches the goalpost.e) Find when and how far away the height of the ball is at 5m

Name: 3) A soccer player kicks a ball at an angle of 37° above the horizont
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Description: 3) A soccer player kicks a ball at an angle of 37° above the horizontal as shown above.= 10m/s²Goalpost25 m/s7.3m40mSin 37° = 0.60Cos 37° = 0.80a) Determine the horizontal and vertical component of the ball's velocity at thestarting point.b) Determi

Answered: a) Determine the horizontal and…

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

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3) A soccer player kicks a ball at an angle of 37° above the horizontal as shown above.
= 10m/s²
Goalpost
25 m/s
7.3m
40m
Sin 37° = 0.60
Cos 37° = 0.80
a) Determine the horizontal and vertical component of the ball's velocity at the
starting point.
b) Determine the maximum height.
c) Determine the time it takes the ball to reach the goalpost.
d) Determine the height of the ball when it reaches the goalpost.
e) Find when and how far away the height of the ball is at 5m

Expert Solution

Step 1

the recatngular resolution of a vector gives two components

v_horizonatal component= v cos $θ$

v_vertical component= v sin $θ$

maximum height of the trajectory is given by

$h = \frac{v^{2} {\sin^{2} θ}^{}}{2 g}$ ......(1)

time taken to cover a certain horizontal distance by trajectory

$t = \frac{d i s \tan c e}{h o r i z o n t a l c o m p o n e n t o f v e l o c i t y}$ .......(2)

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