A Derangement is a permutation of n elements, such that no element appears in its origin For example, a derangement of (0, 1, 2, 3) is {2, 3, 1, 0). Given a number n, find the total number of Derangements of a set of n elements. Input Specification: input1: N, the number of Objects Output Specification: Return the number of arrangements in which no object occurs at its original

A Derangement is a permutation of n elements, such that no element appears in its origin For example, a derangement of (0, 1, 2, 3) is {2, 3, 1, 0). Given a number n, find the total number of Derangements of a set of n elements. Input Specification: input1: N, the number of Objects Output Specification: Return the number of arrangements in which no object occurs at its original

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Create the following graph. Implement the following functions. 1. addEdge() that takes two vertices as two parameters and creates an Edge between them. 2. nonAdjacentVertices() that takes a single vertex as parameter, and returns an array of vertices that are NOT adjacent to that vertex. 3. Write a function addUnknownVertices() that takes a vertex as a parameters, and creates an Edge with the vertices that are NOT adjacent to it. 4. Write a method searchVertex() which takes an array of Vertices as parameters. The first member of the array will be the starting vertex and the last member will be the Vertex you want to reach. For example searchVertex(Vertex 0, Vertex 4, Vertex 3) will output “Vertex cannot be reached” since you can reach from 0 to 4, but cannot from 4 to 3. Again, searchVertex(Vertex 0, Vertex 1, Vertex 2, Node 3) will output “Vertex can be reached” since you can reach from 0 to 1, 1 to 2, 2 to 3.
Student Registration Simulation that can add information by the user itself (java.util.scanner) NOTE: ADD ATLEAST 5 STUDENT INFORMATION USING ONLY ARRAY
Coupon collector is a classic statisticsproblem with many practical applications. The problem is to repeatedly pickobjects from a set of objects and find out how many picks are needed for all theobjects to be picked at least once. A variation of the problem is to pick cards froma shuffled deck of 52 cards repeatedly, and find out how many picks are neededbefore you see one of each suit. Assume a picked card is placed back in the deck before picking another. Write a program to simulate the number of picks neededto get four cards from each suit and display the four cards picked (it is possible acard may be picked twice). Here is a sample run of the program: Queen of Spades5 of ClubsQueen of Hearts4 of DiamondsNumber of picks: 12
Task 04: A permutation of a set of distinct objects is an ordered arrangement of these objects. An ordered arrangement of r elements of a set is called an r-permutation. Write a method that takes a string and prints all its permutations. hint: For a string "123" the method returns all its possible permutations as given below. 123 132 213 231 312 321
Use the right loop for the right assignment, using all the follow- ing loops: for, while without hasNext(), while with hasNext() and do-while. So I cannot use array. it has to be done in java.
int binsearch (int X , int V [] , int n ) { int low , high , mid , i ; low = 0; high = n - 1; for ( i = 0; i < high ; i ++) { if( V[ i ] > V [ i +1]) return -2; } while ( low <= high ) { mid = ( low + high )/2; if ( X < V [ mid ]) high = mid - 1; else if ( X > V [ mid ]) low = mid + 1; else return mid ; } return -1; } This code takes as input a sorted array V of size n, and an integer X, if X exists in the array it will return the index of X, else it will return -1. 1. Draw a CFG for binsearch(). 2. From the CFG, identify a set of entry–exit paths to satisfy the complete statement coverage criterion. 3. Identify additional paths, if necessary, to satisfy the complete branch coverage criterion. 4. For each path identified above, derive their path predicate…
Given an array of strings, return all groups of strings that are anagrams. The groups must be created in order of their appearance in the original array. Look at the sample case for clarification. Note: The final output will be in lexicographic order. Example 1: Input:N = 5words[] = {act,god,cat,dog,tac}Output:act cat tac god dogExplanation:There are 2 groups ofanagrams "god", "dog" make group 1."act", "cat", "tac" make group 2.
Suppose that intArray is an array of integers, and length specifies the number of elements in intArray. Also, suppose that low and high are two integers such that 0 <= low < length, 0 <= high < length, and low < high. That is, low and high are two indices in intArray. Write a recursive definition that reverses the elements in intArray between low and high.
a multiset is a collection of objects, just like a set, but can contain an object more than once ( the order of the elements still doesn't matter). for example, {1,1,2,5,5,7} is a multistset of size 6. a. how many sets of size 5 can be made using the 10 numeric digits 0 through 9? b. how many multisets of size 5 can be made using he 10 numeric digits 0 through 9?
int countTripletSumPermutations(int size , int* arr, int tripletSum){int count = 0 ; for(int i = 0 ; i < size - 2; i++) { if (tripletSum % arr[i] == 0) { for (int j =0 ; j < size - 1; j++) { if (tripletSum % (arr[i] * arr[j]) == 0) { int value = tripletSum /(arr[i] * arr[j]); for(int k = j + 1 ; k < size ; k++ ) if (arr[k] == value) count++ ; } } }} return count;}
Implement the Solver class. The point of the solver class is the solve method which takes a board/puzzle configuration represented as a 2D array of bytes and returns a byte array containing a minimal sequence of moves that will lead to the solved board. The 2D array of bytes is “triangular” and represents a valid board configuration. Namely, the 2D array has 5 rows (0 – 4) and the size of every row is 1 more than its index. (e.g. Row 0 has length 1). The array contains one 0, five 1s, four 2s and five 3s. The solve method then returns an array of bytes representing a minimal sequence of moves that solves the puzzle. In other words, if the numbers from the returned array are used in order as inputs to the move method on the Board object representing the initial configuration, the resulting board configuration represents the solved board. Furthermore, the solution must be minimal in the sense that there are no solutions that use fewer moves (although there could be other solutions that…
Do you reach many, do you reach one? def knight_jump(knight, start, end): An ordinary chess knight on a two-dimensional board of squares can make an “L-move” into up to eight possible neighbours. However, we can generalize the entire chessboard into k dimensions from just the puny two. A natural extension of the knight's move to keep moves symmetric with respect to these dimensions is to define the possible moves as some k-tuple of strictly decreasing nonnegative integer offsets. Each one of these k offsets must be used for exactly one dimension of your choice during the move, either as a positive or a negative version.For example, the three-dimensional (4,3,1)-knight makes its way by first moving four steps along any one of the three dimensions, then three steps along any other dimension, and then one step along the remaining dimension, whichever dimensions that was. These steps are considered to be performed together as a single jump that does not visit or is blocked by any of the…