A cubical tank (sides 2 meters) is filled with water to height 10. 0.2 m d H dt -0. 03 H². H(0) = 1.3 %3D using the Taylor method of order 2 Hn+1 = H, + h f (H„) +, f'(H,) Use the step size h = 0.2 and recurse twice to generate H(0. 2) and H(0.4) H = 1.3 m at t = 0. The water is drained through a circular hole with diameter Solve the first degree differential equation

A cubical tank (sides 2 meters) is filled with water to height 10. 0.2 m d H dt -0. 03 H². H(0) = 1.3 %3D using the Taylor method of order 2 Hn+1 = H, + h f (H„) +, f'(H,) Use the step size h = 0.2 and recurse twice to generate H(0. 2) and H(0.4) H = 1.3 m at t = 0. The water is drained through a circular hole with diameter Solve the first degree differential equation

Advanced Engineering Mathematics

10th Edition

ISBN:9780470458365

Author:Erwin Kreyszig

Publisher:Erwin Kreyszig

Chapter2: Second-order Linear Odes

Section: Chapter Questions

Problem 1RQ

See similar textbooks

Similar questions

Find the maximum off(x) = 30x4 − 121x3 + 60x2 + 64x USING Newton’s method (x0 = 4, εs = 1%)
Find all initial conditions such that (x^2-x)y'=(2x-1)y has no solution, precisely one solution, and more than one solution. y'=dy/dx
Solve the non-homogenous system Sa' = -x – y+ 3/2 ly = 2x – 4y Find lim 00 x(t)
y''+6y=6+x By using i) Method of undetermined coefficients ii) Method of variation of parameters Hence verify your answer.
of the following funclion By compuler evaluate numevically bath the T function and the original integral. bepress cach indegrals as exically numeri ē dx Hint: Put x= ll xe Hint : Puk x
Let y = 3e^1/2x - 7e^-X.
Determine the sum/quantity for x∈R and ε>0 : ln^−1((x − ε, x + ε)) := {y > 0 | ln y ∈ (x − ε, x + ε)}. image is the solution: I dont get the transition from 2 to third row. Can someone explain it to me?
x''-4x'+3x=(e^t)/(1+e^t) Using Variation of Parameters method, find the general solution.
The total differential of g(x, y) = e*z²-y is at A(1,4) is %3D Select one: a. dg(A)=(8-1)e^(0) O b. dg(A)=(8xdx-dy)e^(0) c. dg(A)=(8dx-dy)e^(0) O d. dg(A)=(8dx-dy)
Use the method of variation of parameters to find the general solution to the given equation. y''+3y'+2y=1/(1+e^x). Use A and B in your answer to denote arbitrary constants. Can you please help me answer this since I inputted that answer and it was incorrect?
Let y'=sinxy and y(0)=2 Approximate y(4) using Euler's method with step sizes of .25
Find the second solution by reduction of order method: