A cube of side 5 cm each whose upper face is displaced by 0.65 cm due to a force of 0.25 N. Calculate (1) shearing stress, (2) Shearing strain (3) Modulus rigidity
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A: Write the expression for stress.
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Q: 12-23. If the wide-flange beam is subjected to a shear of V = 30 kN, determine the maximum shear…
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Q: Problem 2 ( )A 200 Kg load is hung on a wire of length 4 m, and a cross- sectional area A=4 10- m2.…
A: Stress. = Force ÷ area. Force =weight of load= mg = 200kg×9.8m/s2 = 196N Force = 196N Area = 4 ×…
Q: 2. A steel rod ¾/4" in diameter and 25 ft long is subjected to an axial tensile load of 15,000 lb.…
A: a) Calculate the area of the steel rod. A=π4d2A=π4(34 in)2A=0.4418 in2 Calculate the stress in the…
Q: 10) Assume Young's Modulus for bone is 1.5E10 N/m². The bone breaks if stress greater than 1.5E8 N/…
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Q: A metal slab of side (74+ 75) cm and thickness (74 + 25) cm is subjected to a tangential force of…
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Q: A wooden dowel is subjected to a shearing force of 715N on its top cylindrical face. If the dowel…
A: Shearing force F=715 N, diameter of dowel d=3cm (radius r=1.5cm), height of dowel h=11 cm and shear…
Q: For the given state of stress, determine: (1) The principle stresses and the directions of the…
A: Solution:- 1). In the figure given we have: σx= 350…
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Q: A wire of uniform cross sectional area of 0.25 mm2 is stretched at both ends by a total force of 65…
A: Given data The cross-sectional area is given as Ac = 0.25 mm2. The total force at both ends is…
Q: A tangential force of 0.004 KN affected the upper surface of a rectangle 5 mm high, 3 cm long and 5…
A: Given Dimensions, l=3 cm= 3×10-2mw=5 cm=5×10-2mh=5mm=5×10-3m Tangential force, F=0.004 KN= 4N…
Q: A wire of uniform cross sectional area of 0.15 mm2 is stretched at both ends by a total force of 40…
A: Given, Area of cross section of the wire A = 0.15 mm2 Total force acting on the both end F = 40 N…
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Q: N/m The young's modulus of a material whose elastic strain and stress are 1.45 and 108.96 N/m2…
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Q: 10) A femur bone of length 30 cm and diameter 2.5 cm is subjected to a compressive tress of 1.5 *10…
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Q: rizontal aluminum rod 3.4 cm in diameter projects 7.0 cm from a wall. A 810 kg object is suspended…
A: Given: d=3.4 cm L=7cm =0.07mm=810 kgG=3.0*1010 N/m2
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Q: A wall climber of mass 85 kg dangles at the end of a rope. The rope has a diameter of 9.6 mm, and is…
A: mass= 85 Kg Length, L= 21 m radius, r= 4.8 mm ∆L= 3.2 cm
Q: A steel cable 2.0 m long has a cross-sectional area of 0.07 m2. A 200-kg machine is hung from the…
A: Length of cable L = 2.0 m Cross-sectional area A = 0.07 m2 Mass of machine M = 200 kg Young modulus…
Q: 7-8. A steel wire has the following properties: Length = 5m, Cross section = 0.05 cm2, Young’s…
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Q: A 7-kip · ft torque is applied to a hollow aluminum shaft having the cross section shown. Neglecting…
A: Given data- T=7 kip-ft Radius of outer circle, r0=7 in Radius of inner circle, ri=14 in-4 in-2 in2=4…
Q: A wire of length 2m and cross sectional area 104 m² is stretched by a load 102kg the steel wire is…
A: We have to compute here,(a) Longitudinal stress(b) Longitudinal strain(c) Young's modulusWe have…
Q: Assume Young's modulus of a femure bone of an effective diameter 2.5 cm is 1.5 x1010 N/m2. The bone…
A: Given: A femur bone of an effective diameter 2.5 cm and it's Young's modulus = 1.5 × 1010 N/m2.…
Q: What will be the shear stress value?
A: Apply Hooke law of elasticity
Q: If the equation of a velocity profile over a plate is u=3 y in which the velocity in m/s at a…
A: Given: Velocity, u=3y23 m/s μ=8.4 poise μ=8.4 ×10-1kg/ms To find: Sheer stress at y=0 cm and y=5 cm
Q: The young modulus of a material whose elastic strain and stress are 1.53 and 169.42 N/m²…
A: The elastic strain, strain=1.53 The stress, stress=169.42 N/m2
Q: Hooke's Law may also be stated in the same relation as Young's Modulus where "the strain in a solid…
A: Hooke's law is define as that the strain in a solid body is directly proportional to the applied…
Q: Question 15 Within elastic limit, the shear stress is proportional to shear strain. What is the…
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Q: Tensile load of 2 MN is applied to an Aluminium cord with original diameter of 5 mm, the measured…
A: Given data: Magnitude of tensile load is, F=2 MN=2×106 N Original diameter of Aluminum cord is, d=5…
Q: What is tensile stress? stress that occurs when forces are contracting an object, causing its…
A: Answer is part b
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