A cruise ship with a mass of 1.15 × 107 kg strikes a pier at a speed of 0.75 m/s. It comes to rest over a distance of 6.15 m, damaging the ship, the pier, and the tugboat captain’s finances. Assume a constant acceleration occurs during the collision. 1).Find the average force Fsp being exerted on the pier as the ship hits it, in terms of the time of interaction Δt, the initial velocity of the ship v, and the mass of the ship m. Take the motion of the cruise ship to be in the positive direction.

A billiard ball moving at 5.95 m/s strikes a stationary ball of the same mass. After the collision, the first ball moves at 4.93 m/s, at an angle of 34° with respect to the original line of motion. (a) Find the velocity (magnitude and direction) of the second ball after collision. (Enter the direction with respect to the original line of motion. Include the sign of your answer. Consider the sign of the first ball's angle.) m/s (b) was the collision inelastic or elastic? O inelastic O elastic

A 0.2-kg rubber egg bounces off an actor's roof, remaining in contact with it for 43 ms while changing the egg's velocity from 24.5 m/s directly toward the roof to 13.5 m/s directly away from it. Find the magnitude of the average force applied to the egg by the roof. (Be careful with units!) Fav= = N Record your numerical answer below, assuming three significant figures. Remember to include a "-" when necessary.

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A stone is dropped at t = 0. A second stone, with 3 times the mass of the first, is dropped from the same point at t = 54 ms. (a) How far below the release point is the center of mass of the two stones at t = 270 ms? (Neither stone has yet reached the ground.) (b) How fast is the center of mass of the two-stone system moving at that time?   (a) Number Enter your answer for part (a) in accordance to the question statement Units Choose the answer for part (a) from the menu in accordance to the question statement                                                           This answer has no units° (degrees)mkgsm/sm/s^2NJWN/mkg·m/s or N·sN/m^2 or Pakg/m^3gm/s^3times (b) Number Enter your answer for part (b) in accordance to the question statement Units Choose the answer for part (b) from the menu in accordance to the question statement                                                           This answer has no units° (degrees)mkgsm/sm/s^2NJWN/mkg·m/s or N·sN/m^2 or…

A rocket takes off against the force of gravity. Consider this a non-isolated system. Derive the rocket equation formula relating velocity to the mass of the rocket and time. Let the velocity of the rocket be v(t) and the relative speed of the ejected fuel relative to the moving rocket be u. Ignore air drag.

Problem #4: Consider a frictionless track as shown in the figure below. A block of mass m¡ = 4.00 kg is released from A. It makes a head-on elastic collision at B with a block of mass m2 = 20 kg that is initially at rest. Calculate the maximum height too which m¡ rises after the collision. 5.00 m m2 (B

A man claims that he can hold onto a 13.0-kg child in a head-on collision as long as he has his seat belt on. Consider this man in a collision in which he is in one of two identical cars each traveling toward the other at 50.0 mi/h relative to the ground. The car in which he rides is brought to rest in 0.07 s. (a) Find the magnitude of the average force needed to hold onto the child. N (b) Based on your result to part (a), is the man's claim valid? O This man's claim is nonsense. O This man's claim is legitimate.