Human Anatomy & Physiology (11th Edition)
11th Edition
ISBN: 9780134580999
Author: Elaine N. Marieb, Katja N. Hoehn
Publisher: PEARSON
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A cross was made between a white male dog and two different black females. The first female gave birth to eight black pups, and the second female gave birth to four white and three black pups. What are the likely genotypes of the male parent and the two female parents? Use Punnett’s squares to support your answer. Explain whether you are uncertain about any of the genotypes.
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- Consider the following cross: AaBbCcDdEe X AaBbCcDdEe. How many different phenotypes would you expect in the offspring from this cross? Number of phenotypes =arrow_forwardGive typing answer with explanation and conclusionarrow_forwardA black guinea pig is mated to a white guinea pig, and they produce 12 black offspring Then, the same white guinea pig is mated to a different black guinea pig, and they produce 7 black and 5 white offspring. What is the best explanation for the difference between these two matings? In your answer, you must include genotypes for the parents and offspring of each cross.arrow_forward
- In the same cross as question #1, what fraction of the offspring will have their father's genotype for both traits?arrow_forwardDrag each description to the appropriate column. (Each box is used once.) In the Bb offspring from a monohybrid cross, half the offspring inherited the B allele from the male parent and half from the female parent. Pairs of alleles of different genes segregate into gametes independently of one another. An individual with the genotype Bo will produce two types of gametes gametes with B and gametes with b Alleles of a single gene separate during gamete formation and then unite at random-one from each parent-at fertilization. Two individuals that both have the genotype Bb can produce offspring with genotypes BB, Bb, and bb. Law of Segregation In a cross between Aa Gg dihybrids, aa gg progeny will occur at a frequency of 1/16. An individual having two genes with two alleles each, Bb and Ee, can give rise to four gamete types: B E, B e, b E, and b e. Law of Independent Assortmentarrow_forwardMale cats are either black (B) or orange (O). Females are black, orange, or calico, which has patches of black and orange. Calico is formed from the codominance between the two alleles in the heterozygote, so a calico cat is (XB XO). Give the genotype and phenotype ratio of a cross between an orange male cat and a calico cat.arrow_forward
- You inspect an ear of corn and find the following number of kernels: 461 red and starch, 142 red and sweet, 156 yellow and starchy and 53 yellow and sweet. a. What genotype did the parent corn plants probably have? b. Support your answer by working out the cross with a Punnett squarearrow_forwardA cross is performed between individuals with the following genotypes: Aabb and aaBb. Use a Punnett square and predicted probabilities to answer the following questions. A. What is the probability that an offspring is dominant for the first trait and recessive for the second? B. What is the probability that an offspring is dominant for both traits? C. What is the probability that two offspring are dominant for both traits?arrow_forwardSpotted lanternfly females were crosses with males possessing short wings (sw) ebony body (e) and sephia (s) eyes, which are recessive traits. 1000 offspring were counted, and the results are shown in the table. below. No determination of sex was made. Using proper notation determine the linkage-genotype of the female parent. Determine the sequence of the three genes and map the distances between them. Calculate the COC and interference in the cross and describe what it means. Phenotype ++ e S SW + s + + + sw e + + + S SW e se + sw + #offspring 332 331 111 121 46 56 7 6arrow_forward
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