A cross belt system gives a speed reduction of 6:1 and the centre distance between the pulleys is 2.5 m. The effective radius of the driving pulley is r₂ = 80 mm and it runs at the speed of 550 rpm. The grove angle of pulleys is 25°. The belt has a mass of 0.35 kg/m and the coefficient of friction of 0.3. If the tension in the belt is not to exceed 650 N. calculate the power that can be transmitted by drive.

D B (2 100N AB=10 cm CB=BD=4 cm AF=2cm In the mechanism shown above, the friction coefficient of the sliding limb is given as 0.3. A horizontal force of 100 N is applied from the F point. Calculate the torque required for the AB crank handle to start SYT (Counter Clockwise) motion.

8. Answer the following questions about the exercise of Box A (massmA=50kg) and Box B (mB=10kg) located on the slope as shown in Figure 7. Between slope and box A, the coefficient of static friction is uk, and the angle of slope is 10 degrees, although box A and B are connected in a solid line and ignore the mass of the pulley.1)What is the maximum friction (kgf) between Box A and Slope for us=0.4 and Uk=0.15?2)What is the maximum friction between Box A and the slope (kgf) for us=0.3 and UK=0.15?3)us=0.3 and Uk=0.15 What is the tension in kgf?4)us=0.3 and uk=0.15 when box B goes down 2m, calculate the size (m/s) of the speed of box A and box B using the modified energy supply law.