**Question:**A CPU is equipped with a cache. If it takes 5 ns to access the data from the cache and 60 ns to access data from the main memory, what should be the hit ratio if the effective memory access time is 8 ns?**Answer = ________________%****Explanation:**To find the hit ratio, you can use the formula for effective memory access time:\[ \text{Effective Access Time (EAT)} = (\text{Hit Ratio} \times \text{Cache Access Time}) + ((1 - \text{Hit Ratio}) \times \text{Main Memory Access Time}) \]Given:- Cache Access Time = 5 ns- Main Memory Access Time = 60 ns- Effective Access Time = 8 nsSubstitute the values:\[ 8 = (\text{Hit Ratio} \times 5) + ((1 - \text{Hit Ratio}) \times 60) \]Solve for Hit Ratio:1. Expand the equation: \[ 8 = 5 \times \text{Hit Ratio} + 60 - 60 \times \text{Hit Ratio} \]2. Combine like terms: \[ 8 = 60 - 55 \times \text{Hit Ratio} \]3. Rearrange: \[ 55 \times \text{Hit Ratio} = 60 - 8 \]4. Simplify: \[ 55 \times \text{Hit Ratio} = 52 \]5. Divide both sides by 55: \[ \text{Hit Ratio} = \frac{52}{55} \approx 0.9455 \]Therefore, the hit ratio should be approximately 94.55%.Fill in the answer:**Answer = 94.55%** A CPU is equipped with a cache. If it takes 5 ns to access the data from the cache and 60 ns to access data from the main memory, what is the effective memory access time if the hit ratio is 90%?Answer = _______________ ns[Input box]

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A CPU is equipped with a cache. If it takes 5 ns to access the data from the cache and 60 ns to access data from the main memory. What should be the hit ratio if the effective memory access time is 8 ns? Answer=

A CPU is equipped with a cache. If it takes 5 ns to access the data from the cache and 60 ns to access data from the main memory. What should be the hit ratio if the effective memory access time is 8 ns? Answer=

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A CPU is equipped with a cache. If it takes 5 ns to access the data from the cache and 60 ns to access data from the main memory, what is the effective memory access time if the hit ratio is 90%?

Answer = _______________ ns

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