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A coyote can locate a sound source with good accuracy by comparing the arrival times of a sound wave at its two ears. Suppose a coyote is facing a bird and listening to it whistle at 1000 HzHz . The bird is 3.0 mm away, directly in front of the coyote’s right ear. The coyote’s ears are 15 cmcm apart on a line perpendicular to the right ear-bird line.What is the difference in the arrival time of the sound at the left ear and the right ear? Hint: You are looking for the difference between two numbers that are nearly the same. What does this near equality imply about the necessary precision during intermediate stages of the calculation?What is the ratio of this time difference to the period of the sound wave?

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- One cue your hearing system uses to localize a sound (i.e., to tell where a sound is coming from) is the slight difference in the arrival times of the sound at your ears. Your ears are spaced approximately 20 cm apart. Consider a sound source 5.0 m from the center of your head along a line 45∘ to your right. What is the difference in arrival times? Give your answer in microseconds. Hint: You are looking for the difference between two numbers that are nearly the same. What does this near equality imply about the necessary precision during intermediate stages of the calculation?arrow_forwardWhen two sources located at different positions produce the same pure tone, the human ear will often hear one sound that is equal to the sum of the individual tones. Since the sources are at different locations, they will have different phase angles p. If two speakers located at different positions produce pure tones 元 P, =A, sin (2uft + 1) and P, = A2 sin (2nft + dp2) , where - s41,.427, then the resulting tone heard by a listener can be written as P = A sin (2nft + 4), where A, sin 4, + A, sin p2 4 = arctan (A, cos 4, + A, cos 42)² + (A, sin d, + A2 sin 2) 2 . Complete parts a and b. and A = 1 A, cos , + A2 cos 42 (a) Calculate A and p if A, = 0.0009, , =0.057, A2=0.004, and p2 = 0.68. Also find an expression for P = A sin (2xft + 4p) if f= 220. A = (Do not round until the final answer. Then round to five decimal places as needed.) (Do not round until the final answer. Then round to five decimal places as needed.) Find an expression for P = A sin (2xft + 4) if f= 220. P= (Use…arrow_forwardAn intensity detector can be moved along a straight track. a source of spherical waves is placed at one end of the track. When the detector is 2 m away from the source, it measures an intensity of 80 W/m2. What distance do we need to move the detector from that position to get a measurement 13 dB lower? Answer: 6.95marrow_forward
- Two students are standing the same distance from a source of sound. The first student receives a power of 68 × 10-6 W in their eardrum. The second student receives σ = 1.2 times more power in their eardrum. What is the ratio of the diameters of the students eardrums? d1/d2= If the second students eardrums have a diameter of d=1cm what was the intensity of the sound that the student heard in watts per square meter? I=arrow_forwardTwo progressive waves y (x, t) = A sin( 4 x – ot) and y2(x, t) = A sin(4x - - - ) travel in the same direction. Calculate the speed of the wave produced as a result of interference of these two waves. Take A = 5 cm, 1 = 4 m and w = 31.4 Hz. Provide your answer in Sl units.arrow_forwardThe normal human ear is sensitive to sounds with frequencies from about 20 Hz to about 20,000 Hz. (a) What is the corresponding range of wavelengths in air? (The speed of sound in air is 344 m/s.) ?min = ?max = (b) What is the corresponding range of wavelengths in iron? (The speed of sound in iron is 5130 m/s.) ?min = ?max =arrow_forward
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