A coyote can locate a sound source with good accuracy by comparing the arrival times of a sound wave at its two ears. Suppose a coyote is facing a bird and listening to it whistle at 1000 HzHz . The bird is 3.0 mm away, directly in front of the coyote’s right ear. The coyote’s ears are 15 cmcm apart on a line perpendicular to the right ear-bird line.What is the difference in the arrival time of the sound at the left ear and the right ear? Hint: You are looking for the difference between two numbers that are nearly the same. What does this near equality imply about the necessary precision during intermediate stages of the calculation?What is the ratio of this time difference to the period of the sound wave?
A coyote can locate a sound source with good accuracy by comparing the arrival times of a sound wave at its two ears. Suppose a coyote is facing a bird and listening to it whistle at 1000 HzHz . The bird is 3.0 mm away, directly in front of the coyote’s right ear. The coyote’s ears are 15 cmcm apart on a line perpendicular to the right ear-bird line.What is the difference in the arrival time of the sound at the left ear and the right ear? Hint: You are looking for the difference between two numbers that are nearly the same. What does this near equality imply about the necessary precision during intermediate stages of the calculation?What is the ratio of this time difference to the period of the sound wave?
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