A counterflow heat exchanger is employed to cool 0.55 kg/s (CP = 2.45 kJ/kg-K) of oil from 115°C to 40°C by the use of water. The inlet and outlet temperatures of cooling water are 15°C and 75°C, respectively. The overall heat  transfer coefficient is expected to be 1450 W/m2-°C. Using the NTU method, calculate the following: a. The mass flow rate of water. b. The effectiveness of the heat exchanger c.Surface area required

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Need answer ASAP In a counter-current-flow tubular heat exchanger, a liquid food (milk),flowing in the inner pipe, is heated from 20 to 40°C. In theouter pipe the heating medium (water) cools from 90 to50°C. The overall heat-transfer coefficient based on the insidediameter is 2000 W/(m^2-°C). The inside diameter is 5 cm andlength of the heat exchanger is 10 m. The average specific heatof water is 4.181 kJ/(kg-°C). Calculate the mass flow rate ofwater in the outer pipe.  Compare the amount of milk being heated to concurrent design.

A long, thin-walled double-pipe heat exchanger with tube and shell diameters of 0.01 m and 0.025 m, respectively, is used to condense refrigerant-134a with water at 20°C. The refrigerant flows through the tube, with a convection heat transfer coefficient of hi= 4100 W/m² °C. Water flows through the shell at a rate of 0.3 kg/s. The thermal resistance of the inner tube is negligible since the tube material is highly conductive and its thickness is negligible. Both the water and refrigerant-134a flows are fully developed. Properties of the water and refrigerant-134a are constant. Water properties: p = 998 kg/m³, v=u/p-1.004x 10-6 m²/s, k = 0.598 W/m. °C, Pr = 7.01 Cold water D Do