
College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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![### Magnetic Force on a Current-Carrying Wire
A copper wire of length 25.0 cm is placed in a magnetic field of 0.36 T (tesla). If it has a mass of 11.0 g, what is the minimum current through the wire that would result in a magnetic force equal to its weight?
- Options:
- 12 A
- 0.48 A
- 1.2 A
- 0.75 A
- 3.3 A
This question involves the interaction between electricity and magnetism, specifically how a current-carrying wire experiences a force when placed in a magnetic field. The force can be calculated using the formula:
\[ F = BIL \]
Where:
- \( F \) is the magnetic force,
- \( B \) is the magnetic field strength,
- \( I \) is the current in the wire,
- \( L \) is the length of the wire.
For the wire's weight \( W \) to equal the magnetic force \( F \), we equate \( F \) to \( W = mg \) (where \( m \) is the mass and \( g \) is the acceleration due to gravity).
### Explanation of Options
- Calculate the force necessary to counteract the wire's weight using its given mass.
- Use the relationship \( F = BIL \) to solve for \( I \), and identify which of the provided options matches the calculated current.](https://content.bartleby.com/qna-images/question/2c067e04-819e-445d-9345-defba0ea4f93/f99dc619-7871-4b0b-86dc-b65a4f56d291/fyc6m1_thumbnail.jpeg)
Transcribed Image Text:### Magnetic Force on a Current-Carrying Wire
A copper wire of length 25.0 cm is placed in a magnetic field of 0.36 T (tesla). If it has a mass of 11.0 g, what is the minimum current through the wire that would result in a magnetic force equal to its weight?
- Options:
- 12 A
- 0.48 A
- 1.2 A
- 0.75 A
- 3.3 A
This question involves the interaction between electricity and magnetism, specifically how a current-carrying wire experiences a force when placed in a magnetic field. The force can be calculated using the formula:
\[ F = BIL \]
Where:
- \( F \) is the magnetic force,
- \( B \) is the magnetic field strength,
- \( I \) is the current in the wire,
- \( L \) is the length of the wire.
For the wire's weight \( W \) to equal the magnetic force \( F \), we equate \( F \) to \( W = mg \) (where \( m \) is the mass and \( g \) is the acceleration due to gravity).
### Explanation of Options
- Calculate the force necessary to counteract the wire's weight using its given mass.
- Use the relationship \( F = BIL \) to solve for \( I \), and identify which of the provided options matches the calculated current.
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