A cooler at a picnic contains 100 cans of soda covered by ice. There are 40 cans of cola, 32 cans of orange soda, 16 cans of ginger ale, and 12 cans of root beer. The cans are all the same size and shape. If one can is selected at random from the cooler, determine the probability that the soda selected is orange soda, ginger ale, or cola. The probability that the can selected is a orange soda, ginger ale, or cola is. (Simplify your answer. Type a fraction.)
A cooler at a picnic contains 100 cans of soda covered by ice. There are 40 cans of cola, 32 cans of orange soda, 16 cans of ginger ale, and 12 cans of root beer. The cans are all the same size and shape. If one can is selected at random from the cooler, determine the probability that the soda selected is orange soda, ginger ale, or cola. The probability that the can selected is a orange soda, ginger ale, or cola is. (Simplify your answer. Type a fraction.)
College Algebra
7th Edition
ISBN:9781305115545
Author:James Stewart, Lothar Redlin, Saleem Watson
Publisher:James Stewart, Lothar Redlin, Saleem Watson
Chapter9: Counting And Probability
Section9.2: Probability
Problem 54E
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Transcribed Image Text:A cooler at a picnic contains 100 cans of soda covered by ice. There are 40 cans of cola, 32 cans of orange soda, 16 cans of ginger ale, and 12 cans of root beer. The cans are all the same size and shape. If one
can is selected at random from the cooler, determine the probability that the soda selected is orange soda, ginger ale, or cola.
...
The probability that the can selected is a orange soda, ginger ale, or cola is.
(Simplify your answer. Type a fraction.)
Transcribed Image Text:The graduates at a southern university are shown in the table.
Art & Science
A
Education
E
Business
B
Total
Male, M
342
424
682
1448
Female, F
324
102
144
570
Total
666
526
826
2018
A student is selected at random from the graduating class. Find the probability that the student is female, given that the student is receiving an education degree, P(F|E).
...
724
51
O A. P(FJE)=
B. P(F|E) =
1009
263
570
324
OC. P(F|E) =
2018
D. P(F|E) =
666
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