College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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- A contact lens is made of plastic with an index of refraction 1.50. The lens has an outer radius of curvature of + 1.65 cm and an inner radius of curvature of + 5.85 cm. What is its focal length? TTTT Paragraph Arial 3 (12pt) E - E - T- 回i 公 T T, Bullet List O f. Mashups- HTML CSSarrow_forwardplease help asaparrow_forwardA double convex lens has radii of 5 cm and 20 cm, a thickness of 2 cm and an index of 1.5. Locate the principal planes and focal points and compute the image distance for an object 16.4 cm in front of V₁. Determine the ffl and bfl.arrow_forward
- A converging lens is placed 36.0 cm to the right of a diverging lens of focal length 7.0 cm. A beam of parallel light enters the diverging lens from the left, and the beam is again parallel when it emerges from the converging lens. Calculate the focal length of the converging lens. f = _____ cmarrow_forwardCompute the focal length of a diverging thin lens made of flint glass, whose refractive index is 1.66 and is immersed in air having refractive index 1. The radii of the spherical surfaces of the lens are 10 cm and 20 cm. Select one: O -30 cm O O -10 cm 30 cm 10 cmarrow_forwardnot a graded assignmentarrow_forward
- (a) A 1.00 cm-high object is placed 4.35 cm to the left of a converging lens of focal length 7.85 cm. A diverging lens of focal length -16.00 cm is 6.00 cm to the right of the converging lens. Find the position and height of the final image. cm---Select--- position height Is the image inverted or upright? upright inverted Is the image real or virtual? real virtual cm (b) What If? If an image of opposite characteristic, i.e., virtual if the image in part (a) is real and real if the image in part (a) is virtual, is to be obtained, what is the minimum distance (in cm), and in which direction, that the object must be moved from its original position? cm distance direction ---Select---arrow_forwardA 1.00-cm-high object is placed 3.95 cm to the left of a converging lens of focal length 7.80 cm. A diverging lens of focal length –16.00 cm is 6.00 cm to the right of the converging lens. Find the position and height of the final image. position 7.5 cm in front of the second lens v 0.5466 height Calculate the magnification produced by each lens. Then consider how the magnification relates image size and object size for each lens to find the height of the final image. cm Is the image inverted or upright? upright O inverted Is the image real or virtual? real virtualarrow_forwardTwo converging lenses, both with focal lengths 34.9 cm are placed a distance 78.9 cm apart. An object is placed 87.5 cm from the 1st lens. Where is the final image located relative to the 2nd lens? Let + be the back side and - be the front side regarding this distance from the 2nd lens. Measure this in cm.arrow_forward
- Two lenses (f1=100 mm, f2=-150 mm) are used to form an image of a candle on an observation screen. The distance between the lenses is kept small and is measured to be 3.5 cm. The distance of the candle from the center of both lenses is measured to be 82 cm. The distance of the image from the center of both lenses is measured to be 22 cm. (i) What are the experimental focal length of the two combined lenses? (a) 60 mm (b)1040 mm (c) 576.43 mm (d) 173.47 mm (ii) What are the theoretical focal lengths of the two combined lenses? (a) -50 mm (b) 176.47 mm (c) 280.37 mm (d) 52.63 mmarrow_forward(a) For a diverging lens (f = - 16.0 cm), find the image distance for an object that is 16.0 cm from the lens. (b) Determine the magnification of the lens.arrow_forward
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