A container with a volume of 1.60 L was evacuated and then filled at low temperature with 0.0460 mol liquid dinitrogen tetroxide N2O4,. As the temperature was raised, this substance formed nitrogen dioxide N02,: If the pressure of this reaction mixture at equilibrium at 25.0°C was 0.848 atm, what was the total moles of gas in this mixture? 0.0554 MOL What are the moleS of NO2 and moles of N2O4? 0.0188 mol of NO2 0.0366 mol of N2O4 What are the partial pressures of NO2 and N2O4? Partial pressure of NO2=___0.289___atm Partial pressure of N2O4=__0.559_____atm What is Kp at 25.0°C?
A container with a volume of 1.60 L was evacuated and then filled at low temperature with 0.0460 mol liquid dinitrogen tetroxide N2O4,. As the temperature was raised, this substance formed nitrogen dioxide N02,: If the pressure of this reaction mixture at equilibrium at 25.0°C was 0.848 atm, what was the total moles of gas in this mixture? 0.0554 MOL What are the moleS of NO2 and moles of N2O4? 0.0188 mol of NO2 0.0366 mol of N2O4 What are the partial pressures of NO2 and N2O4? Partial pressure of NO2=___0.289___atm Partial pressure of N2O4=__0.559_____atm What is Kp at 25.0°C?
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A container with a volume of 1.60 L was evacuated and then filled at low temperature with 0.0460 mol liquid dinitrogen tetroxide N2O4,. As the temperature was raised, this substance formed nitrogen dioxide N02,:
If the pressure of this reaction mixture at equilibrium at 25.0°C was 0.848 atm, what was the total moles of gas in this mixture? 0.0554 MOL
|
What are the moleS of NO2 and moles of N2O4? |
0.0366 mol of N2O4
What are the partial pressures of NO2 and N2O4?
Partial pressure of NO2=___0.289___atm
Partial pressure of N2O4=__0.559_____atm
What is Kp at 25.0°C?
Expert Solution
Step 1
Given: Volume of container = 1.60 L.
Temperature = 25.0 oC.
Moles of N2O4 taken initially = 0.0460 mol.
And total pressure at equilibrium = 0.848 atm.
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Solved in 3 steps
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