A constant applied force F, of 15.0 N pushes a box with a mass m = 7.00 kg a distance x = 15.0 m across a level floor. The coefficient of kinetic friction between the bOx and the floor is 0.150. F, m Assuming that the box starts from rest, what is the final velocity vf of the box at the 15.0 m point? Uf = m/s If there were no friction between the box and the floor, what applied force Fnew Would give the box the same final velocity? Fnew =

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Chapter5: Newton's Law Of Motion
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A constant applied force ?p of 15.0 N pushes a box with a mass ?=7.00 kg a distance x=15.0 m across a level floor. The coefficient of kinetic friction between the box and the floor is 0.150. Assuming that the box starts from rest, what is the final velocity ?f of the box at the 15.0 m point? If there were no friction between the box and the floor, what applied force Fnew would give the box the same final velocity? 

A constant applied force F, of 15.0 N pushes a box with a mass m =
coefficient of kinetic friction between the box and the floor is 0.150.
7.00 kg a distance x = 15.0 m across a level floor. The
m
Assuming that the box starts from rest, what is the final velocity vf of the box at the 15.0 m point?
Uf =
m/s
If there were no friction between the box and the floor, what applied force Fnew would give the box the same final velocity?
Fnew
N
Transcribed Image Text:A constant applied force F, of 15.0 N pushes a box with a mass m = coefficient of kinetic friction between the box and the floor is 0.150. 7.00 kg a distance x = 15.0 m across a level floor. The m Assuming that the box starts from rest, what is the final velocity vf of the box at the 15.0 m point? Uf = m/s If there were no friction between the box and the floor, what applied force Fnew would give the box the same final velocity? Fnew N
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