A connected graph has 40 even vertices and no odd vertices. Determine whether the graph has an Euler path (but not an Euler circuit), an Euler circuit, or neither an Euler path nor an Euler circuit, and explain why. www. The described graph has an Euler circuit. an Euler path (but not an Euler circuit). neither an Euler path nor an Euler circuit. By Euler's theorem, this is because the graph has more even vertices than odd vertices. more than two even vertices. no odd vertices. à O O O

The graph shown has at least one Euler circuit. Determine an Euler circuit that begins and ends with vertex C. Complete the path so that it is an Euler circuit. C, A, B, E, D, A, 0 ... (.... D B E

Examine the graph to the right. a. Determine whether the graph has an Euler path, an Euler circuit, or neither. b. If the graph has an Euler path or circuit, use trial and error or Fleury's algorithm to find one. The graph has an Euler circuit. The graph has an Euler path (but not an Euler circuit). The graph has neither an Euler path nor an Euler circuit CADB Drag the correct answers into the boxes below. If an Euler path or an Euler circuit exists, drag the vertex labels to the appropriate locations in the path. If no path or circuit exists leave the boxes in part (b) blank a. Does the graph have an Euler path, an Euler circuit, or neither? b. If the graph has an Euler path or an Euler circult, use trial and error or Fleury's algorithm to find one starting at A

Discrete Math:

Does the following graph have an Eulerian circuit? An Eulerian path? If so give the circuit / path.