College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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A concave lens refracts parallel rays in such a way that they are bent away from the axis of the lens. For this reason, a concave lens is referred to as a diverging lens.
Part C: What is the magnification m produced by the concave lens described in Part B? (Expressed numerically)
Part D: Where should the object be moved to have a larger magnification?
The object should be moved closer to the lens. |
The object should be moved farther from the lens. |
The object should be moved to the focal point of the lens. |
The object should not be moved closer to the lens than the focal point. |
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- Suppose you have a concave mirror as shown in the image below. If h = 1.84m is the height of an object (really the displacement of the top of the object from the axis) and h' = 4.21m is the height of the image, what is the magnitude of the transverse magnification (in units of meters)? Image Objectarrow_forwardTwo plane mirrors are at an angle of 0, = 65.6° with each other as in the side view shown in the figure below. If a horizontal ray is incident on mirror 1, at what angle 0, does the outgoing reflected ray make with the surface of mirror 2? Mirror 1 Mirror 2arrow_forwardFigure 5 shows a double concave lens, and an object is placed at the point O. The focal points of this lens are at the points F and F', and the center of the lens is at the point C. Draw the image of this object. F' A Figure 5: Farrow_forward
- Part A A converging lens with a focal length of 60 cm and a diverging lens with a focal length of -50 cm are 290 cm apart. A 3.5-cm-tall object is 80 cm in front of the converging lens. Calculate the image position relative to the diverging lens. Express your answer to two significant figures and include the appropriate units. Enter a positive value if the image is on the other side from the lens and a negative value if the image is on the same side. HẢ ? s'2 Value Units %D Submit Request Answer Part B Calculate the image height. Express your answer to two significant figures and include the appropriate units. HA h' = Value Units %3D Submit Request Answerarrow_forwardThe following figure shows an object near a different thin lens, and one of the principal rays. The tick marks are 3 cm apart. Calculate the magnification of the lens. object lensarrow_forwardAn object stands on the common central axis of two thin, symmetric lenses. The object is placed 15.0 cm in front of the first lens (converging lens) whose focal length is 10.0 cm. The second lens is a diverging lens whose focal length is also 12.0 cm. The distance between the lenses is 40.0 cm. a.) Determine the characteristics of the final image by using thin-lens and magnification equations. Give your reasoning. b.) Find the location of the final image by using ray diagrams (sketch the rays clearly). Object f₁ 15 cm 1st Lens f₁ 40 cm 420 2nd Lensarrow_forward
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