A compound shaft consists of brass segment (1) and aluminum segment (2). Segment (1) is a solid brass shaft with an allowable shear stress of 60 MPa. Segment (2) is a solid aluminum shaft with an allowable shear stress of 90 MPa. If a torque of TC = 23,000 N-m is applied at C, determine the minimum required diameter of (a) the brass shaft and (b) the aluminum shaft.

I need problems 7, 8, and 9 answered pertaining to the print attached below.

Gentlemen, please help to solve a,b,c as I faced confusing questions about screw jack. Conditions are: screw jack is lifting 3.2 tonnes, screw pitch is 12 mm, diameter of the screw is 5 mm. Coefficient of friction was not given but I think we will need it for total force calculation, lets take it 0.2. a) Calculate horizontal component to move the load - what is ment here by horizontal component? b) Calculate vertical component to move the load - what is ment here by vertical component? c) Total force needed to move the load with a lever of 0.82m d) Velocity ratio (VR=distance by effort/distance by load)       Distance by effort (lever)=2 x 3.14 x 0.82 = 5.15m       Distance by load = pitch= 12mm= 0.012 m        VR=5.15/0.012= approx 429. e) Calculate efficiency. For this we need to have MA       (mechanical advantage). It can be calculated when we know total force.          Efficiency=Load (3200 x 9.8) / effort

Please answer part c and e onwards with working out and answer and please label the parts as you have answered a,b,d

You are given a metal rod, cut to a length of 12 in plus/minus .25in. Then you need to cut off 2 in with an accuracy of plus/minus .25 tolerance. You end up with a 10 in rod but what is the tolerance? (hint: rely on the basic principle of tolerance

Build the following part. Report the mass in pounds. Assume all dimensions are in inches. The material is Vanadium. (Located in the "Other Metals" folder in the material properties.) A = 1.72 B = 1.4 2.40 1.20 T .75 TYP 1.20 TYP .70 -1.00 TYP A A A+3.25 R.35 TYP -R.65 TYP CBORE FOR 5/16 HEX HEAD BOLT Ø.332 THRU ALL LØ813 V 235 .10- SECTION A-A 23. B B+1

Two lengths of steel are aut off firm a 187.573" length for a job. Piece1 is a5.729" long and piece 2 is 58.137" long. what is the to tal length of pipe used for the job?

Can some one please help to solve this question following the directions and showing neat work and formulas. PLEASE AND THANK YOU!!!

Can someone please help to solve this question following the directions and showing neat work and formulas and drawing all needed diagrams. PLEASE AND THANK YOU!!!