A compound curve is having a common tangent of 84.50 meters long. The central angles made by the common tangent for the first and second simple curve is 16o and 20o respectively. The length of the tangent of the first curve is 38.60 meters and Sta. PI is 10+180. Find the following: Length of curve from PC to PT Station of PC Station of PCC Station of PT

A compound curve is having a common tangent of 84.50 meters long. The central angles made by the common tangent for the first and second simple curve is 16o and 20o respectively. The length of the tangent of the first curve is 38.60 meters and Sta. PI is 10+180. Find the following: Length of curve from PC to PT Station of PC Station of PCC Station of PT

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

The stationing of the PC of the simple curve is 2+138.5, what is the stationing of point 1 on the curve.
Two tangents that intersect at an angle of 44deg 36’ are to be connected by a compound curve. The tangent at the beginning of the curve at the P.C. is 125.70 m long and that at the P.T. is 155.6 m long. The degree of curvature of the first curve at P.C. is 4deg. Using Arc basis, Determine the radius of the first curve. 286.479 m 150.58 m 322.62 m 445.42 m
Two Tangents intersects at Sta. 0+550. A compound curve laid on their tangents has the following data. I1 = 31°, I2 = 36°, D1 = 3°, D2 = 5° a) Compute the stationing of P.C, P.C.C and P.T b) If the P.T is moved 15 m out , compute the station of the P.T within the P.C.C on the same point. Show a Clear and Organized solution:
The angle of intersection of the tangent lines of a simple curve is 44°. If the offset distance from the PT to the tangent line passing through PC is 120 m, solve for the ff: C. Stationing of the PT if the vertex of the curve is at 10+010.10.
A horizontal curve is designed with a 2,000-ft radius and A = 18°. The curve has a tangent length of 750 ft, and the PI is located at station 20+30. What is the stationing of the PT?
An unsymmetrical parabolic curve has a forward tangent of -8% and a backward tangent of 5%. The length of the curve on the left side (PVC) is 60m. and the vertex is at station 0+500 is at elevation of 100m. The elevation of the road just below the vertex is 97.3m. а. Calculate the total length of the unsymmetrical curve. b. Find the stationing of the highest point. С. Find the elevation of station 0+550.
A compound curve has vertex angles of the first and second curve of 12°30' and 09°30', respectively. Stationing at the point of compound curve is at 11+135.92m. Degrees of curve are 3°30' and 4°00' for the first and second curve, respectively. It is desired to substitute the compound curve with a simple curve that shall end with the same P.C. Determine the: a. Total length of the simple curve b. Station the old P.C. and the New P.T.
The long chord of a compound curve is 425m long and the angles it makes with tangents of the curve are 20° and 24°, respectively. Find the radius R1 of the compound curve if the common tangent is parallel to the long chord. O 679.19m 473.78m O 1152.97m 394.49m
Point A is the point of intersection of the tangents. Two tangents AB and AC are connected bya compound curve. Angle ABC is 30 degrees and angle ACB is 40 degrees. Distance BC is 200mand the radius of the second curve is 100m. Determine the central angle of the first curve.
A compound curve has vertex angles of the first and second curve of 12°30' and 09°30', respectively. Stationing at the point of compound curve is at 11+135.92m. Degrees of curve are 3°00' and 4°00' for the first and second curve, respectively. It is desired to substitute the compound curve with a simple curve that shall end with the same P.C. Determine the: a. Total length of the simple curve b. Station the Old P.C. and the New P.T.
A compound curve is having a common tangent of 104.78 meters long. The central angles made by the common tangent for the first and second simple curve is 18° and 29° respectively. The length of the tangent of the first curve is 30.21 meters and Sta. Pl is 10+180. Determine: - length of tangent (T2) - length of chord (c1) -length of chord (c2)
SOLVE AND ANSWER CORRECTLY. PROVIDE THOROUGH SOLUTION. KINDLY ANSWER ALL