A company wants to manufacture a tin with a square base and top, each of side length r, and rectangular sides. The material for the sides costs 3 dollars per ft. The material for the top and bottom costs 4 dollars per ft². The tin is said to have volume 5 ft. (Recall that the volume of a box is length x width x height.) The dimensions of the cheapest such container can be found by: 60 A. minimizing the function C(z)= 4r² + 60 B. minimizing the function C(r) = 4r2 + I on (0,00) on (0,00) C. minimizing the function C(z) = 8r²+-on (0,00) 60 D. minimizing the function C(z)=8r²+ on (0,00) I E. minimizing the function C(z)=8²+ on (0,00)

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