A company anticipates there will be a demand for 20,000 copies of a certain book during the next year/. It costs the company $0.50 to store a book for 1 year. Each time it must print additional books, it costs $200 to set up the equipment. NOTE: We assume that the demand is uniform. Let • * = number of books printed during each printing run • y = number of printing runs

EBK CONTEMPORARY FINANCIAL MANAGEMENT
14th Edition
ISBN:9781337514835
Author:MOYER
Publisher:MOYER
Chapter18: The Management Of Accounts Receivable And Inventories
Section: Chapter Questions
Problem 17P
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Last Question that I wasnt able to take a picture of says:

What is the minimum total cost?

Use the Inventory Control information above to answer this question.
How many books should be produced during each printing run to minimize
total cost?
books
Question 18
Use the Inventory Control information above to answer this question.
How many printing runs should be done?
printing runs
Transcribed Image Text:Use the Inventory Control information above to answer this question. How many books should be produced during each printing run to minimize total cost? books Question 18 Use the Inventory Control information above to answer this question. How many printing runs should be done? printing runs
Inventory Control
A company anticipates there will be a demand for 20,000 copies of a certain
book during the next year/. It costs the company $0.50 to store a book for 1
year. Each time it must print additional books, it costs $200 to set up the
equipment.
NOTE: We assume that the demand is uniform.
Let
• * = number of books printed during each printing run
• y = number of printing runs
Transcribed Image Text:Inventory Control A company anticipates there will be a demand for 20,000 copies of a certain book during the next year/. It costs the company $0.50 to store a book for 1 year. Each time it must print additional books, it costs $200 to set up the equipment. NOTE: We assume that the demand is uniform. Let • * = number of books printed during each printing run • y = number of printing runs
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