A commuter backs her car out of her garage with an acceleration of 1.40 m/s². (a) How long does it take her to reach a speed of 2.00 m/s? (b) If she then brakes to a stop in 0.800 s, what is her acceleration?

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A: Given data The constant speed of the cop car is u = 110 km/h. The time duration when it passes is…

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A: NOTE: According to the guidelines we are allowed to answer only the first 3 subparts. If you want to…

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A: The distance covered by the car in last 2.0 seconds can be calculated using given steps.

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A: We know that:

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A: Given information:Distance required to come to rest (s) = 4.5 km = 4500 m.Time required to stop (t)…

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A: Given :- speed on sand = 1.20 m/s distance = 48 m walk on pavement = 102 m  average speed of entire…

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A: initial velocity = V0= 0 m/s time = t = 10 sec final velocity = V = 9 m/s

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A:

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Q: (a) How far is the train in first 30sec? (b) What is the average velocity of the train for the…

A:

Q: An unwary football player collides with a padded goalpost while running at a velocity of 6.50 m/s…

A: (a) From kinematics, the formula for the final velocity of the player be:

Q: ball is thrown up at 70 m/s. It goes up and then falls to its original height. (a) How long does it…

A: As per our guidelines, we are supposed to answer only first three subparts in case of multiple…

Q: A certain freely falling object, released from rest, requires 1.50 s to travel the last 30.0 m…

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Q: shut for 0.35 s. If you are driving a car at 69 km/h during such a sneeze, how far does the car move…

A: Speed = distance traveled /time taken Time taken =0.35 sec  Speed =69km /h           = 69 ×1000/3600…

Q: (a) The velocity of a particle changes from vı = 2î + 5f -3k m/s to v2 = 5î - 7j+ 2k m/s in 2 s.…

A: Given: Part a) Part b)

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A: Given: The mass of the runner is 55.7 kg. The initial velocity of the runner is 0 m/s. The…

Q: An unwary football player collides with a padded goalpost while running at a velocity of 7.50 m/s…

A: Answer is uploaded in the 2nd step

Q: Consider the given grap the following: 1. The acceleration from 0 s to 2 s 2. The acceleration from…

A: This problem can be solved using basic formula of linear acceleration and distance.

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A: It is given that, s=40 mt=4.5 sv=2.8 m/s

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Q: During a hard sneeze, your eyes might shut for 0.31 s. If you are driving a car at 81 km/h during…

A: Given data The time interval of a hard sneeze is given as t = 0.31 s. The speed of the car is given…

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Q: You purchase a used car.  After handing over the cash, you drive it away from the lot, starting at…

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Q: A commuter backs her car out of her garage with an acceleration of 1.40 m/s^2. (a) How long does it…

A: Acceleration of the car (a) = 1.40 ms2Initial speed (u) = 0 msFinal speed (v) = 2 ms

Q: The position of a particle for t > 0 is given by r⃗ (t) = 43.02i + 7.0 t3j + 5.0 t-2k̂ m.( a)What is…

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