A common-source amplifier is fed from a signal source having a resistance Rsig = 100 ka and has aload resistance R = 100 k2. The MOSFET has Cgs = 0.1 pF, Cgd = 50 fF, gm = 1 mA/V, and r, = 100kQ. The total capacitance between the output node and ground is C = 0.1 pF.%3DFind the midband gain.

Answered: A common-source amplifier is fed from a…

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

See similar textbooks

Related questions

Question

A common-source amplifier is fed from a signal source having a resistance Rsig = 100 ka and has a
load resistance R = 100 k2. The MOSFET has Cgs = 0.1 pF, Cgd = 50 fF, gm = 1 mA/V, and r, = 100
kQ. The total capacitance between the output node and ground is C = 0.1 pF.
%3D
Find the midband gain.

Expert Solution

Step 1

The small-signal equivalent circuit of the common source amplifier is shown below:

On applying the K.C.L at the output,

$\frac{V_{o}}{R_{L}} + \frac{V_{o}}{r_{o}} + g_{m} V_{g s} = 0 V_{o} (\frac{1}{R_{L}} + \frac{1}{r_{o}}) = - g_{m} V_{g s} \frac{V_{o}}{V_{g s}} = \frac{- g_{m}}{(\frac{1}{R_{L}} + \frac{1}{r_{o}})} \frac{V_{o}}{V_{g s}} = \frac{- g_{m} (R_{L} r_{o})}{R_{L} + r_{o}} \frac{V_{o}}{V_{i n}} = \frac{- g_{m} (R_{L} r_{o})}{R_{L} + r_{o}}$

Trending now

This is a popular solution!

Step by step

Solved in 2 steps with 1 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, electrical-engineering and related others by exploring similar questions and additional content below.

Similar questions