3 decimal places A closed traverse has the following data: Determine thecorrected latitude of DE by compass rule.Total Latitude = 1726.8Total Departure = 1876.3Perimeter = 2628.5For line DE:Distance = 518.4 mLat-0.56%3DDep = +0.34Latitude = 259.20Departure = 448.9%3DO 259.31O 259.28O 259.20O 1726.8

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Answered: A closed traverse has the following…

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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A closed traverse has the following data: Lat=-0.65, Dep=+0.34 Σ[LAT]=1726.8, Σ[DEP]= 1876.3, PERIMETER=2628.5 FOR A LINE DE: DISTANCE= 518.40 m., Lat= 259.20 N, Dep Determine the corrected latitude of DE by transit rulea. 259.310 b. 259.116 c. 259.286 d. 259.090
Use DMD & DPD Method to calculate the Area of the closed traverse whose data is given below. Draw the figure. LINE CORRECTED DEPARTURE CORRECTED DISTANCE 413.53341 596.41168 AB CORRECTED LATITUDE +296.42872 - 246.85339 + 104.50281 154.07815 + 288.33990 BC CD +542.92753 - 597.93576 - 233.33167 606.99919 DA 279.61356
PROBLEM 1. Given in the accompanying tabulation are the adjusted latitude and adjusted departure of a closed traverse. Calculate the area by the DMD method LINE ADJ ADJ LAT DEP AB - 125.055 + 196.387 BC +20.241 + 241.003 CD +180.107 + 65.326 DE +210.169 - 104.519 EF -74.003 - 260.516 FA - 211.459 - 137.681
3. Complete the table and sketch the traverse, assuming no measurements were obtained for line EF. LATITUDE DEPARTURE LINE LENGTH, m BEARING N (+) S() E(+) W(-) АВ N 5°30'8.33" E 490.71 47.27 BC 587.12 608.89 CD 327.41 786.78 DE 1002.76 218.32 EF FA 375.01 544.64 SUM
3. The following tabulated data is to be used in determining the area of traverse ABCDE by the DMD method. Determine the total area of the traverse in m?. Adjusted Latitude Adjusted Departure Course +N -S +E -W АВ 558.25 78.34 ВС 102.58 746.38 CD 285.33 319.24 DE 352.05 395.68 EA 23.45 591.60 Sums +660.83 m -660.83 m +1065.62 m -1065.62
A close triangular traverse has the following data: LINE BEARING DISTANCE АВ N 60° E 1000m BC Due South CA N 60° W An area of 320,000 square meter is cut-off starting from corner A to point F on the line BC. 7. What is the length of line AF? A. 812.4m B. 945.6m C. 898.4m D. 942.6m
A closed traverse was surveyed and the resulting values of latitudes and departures were computed. Determine the correct bearing of line CD using compass rule. LINE BEARING DISTANCE LATITUDE DEPARTURE А-В N 77 38' E 907.00 + 194.25 885.95 В-С S 46 20' W 249.00 - 171.92 180.12 C-D S 10 43' E 348.00 - 341.93 + 64.71 D-E S 84 43' W 523.00 - 48.16 520.78 E-A N 37 01' W 444.80 + 355.16 267.79
Bearing Angle Traverse Given the tabulated measurement of the closed traverse as shown. Determine the Area of the Traverse. Line Length Bearing AB 589.060 m N 87°30’ E BC 391.730 m N 07°02’ E CD 291.860 m N 30°30’ E DE 656.980 m S 42°45’ E EF 654.060 m Unknown FA 686.660 m Unknown Note: EXPRESS YOUR ANSWER UPTO 3 DECIMAL PLACES.
A traverse has the following survey notes. Using the compass rule, determine the adjusted latitude of CD. * Course Bearing Distance АВ N 53.450E 59.800 S 66.900 S 29.133 W 76.580 N 52.000 W 95.780 BC E 70.360 CD DA O -66.913 O -66.940 O -66.939 O -66.931
Q: Use the survey traverse information shown below and calculate: 1. All Partial Co-ordinates for B, C, D and E 2. Length and bearing of line EA Show calculation process with answers. Point A ABCDE D E N 6200.000 D C E 1450.000 Line AB BC CD DE EA Bearing 55°21'32" 93°18'26" 206°41'23" 265°32'45" Distance 318.384 325.544 458.791 276.513
From the field notes of a closed traverse shown below, adjust the traverse: DISTANCES Due North 400.00 m 800.00 m 700.00 m 600.00 m 966.34 m LINES BEARING АВ ВС N45°E S60°E CD DE S20°W EA S86°59'W a. Compute the correction of latitude on line CD using transit rule. b. Compute the correction of latitude on line CD using compass rule. c. Compute the linear error of closure. d. Compute the relative error of precision.
Bearing Angle Traverse Given the tabulated measurement of the closed traverse as shown. Determine the area of the traverse using DPD Method. Line Length Bearing AB 413.600 m N 09°30’ W BC 304.380 m N 55°06’ W CD 407.210 m S 57°35’ W DE Unknown S 04°05’ E EA 649.630 m Unknown Note: EXPRESS YOUR ANSWER UPTO 3 DECIMAL PLACES.

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A closed traverse has the following data: Determine the corrected latitude of DE by compass rule. Total Latitude = 1726.8 Total Departure = 1876.3 Perimeter = 2628.5 For line DE: Distance = 518.4 m Latitude = 259.20 Departure = 448.9 Lat = -0.56 %3D Dep = +0.34 %3D O 259.31 259.28 O 259.20 1726.8