A closed tank contains 3 fluids: Fluid 1 is water (s= 1 and depth is 2 m); Fluid 2 is oil (s- 0.85 and depth is 3 m); Fluid 3 is air having pressure of 20 kPa. An open manometer with mercury as its base fluid is connected to the side of the tank at the lower portion where water is located. The deflection of the mercury is toward the open end of the manometer, where the level of contact with the water

Define the basic barometer?

5. U-shaped manometer pressure gauge contains oil with a specific gravity of 0.95. A gas container is connected to one side of the pressure gauge and the other is in the atmosphere. The height of the oil connected to the atmosphere is 500mm higher than the height of the oil on the gas container side. What is the pressure of the gas in the container when the atmospheric pressure is 765mmHg? (However, gravity + 1 7 5 2 6 9.81m/s^ 2)

With the manometer reading as shown in Fig. 2.33, calculate the difference of pressures in the two tubes A and B containing water. [Ans. 9.07 kPa] 1.65 m 80.25 m T 0.5,m & -Oil sp. gr. 0.9 Water-- Fig. 2.33. B