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A closed cycle is executed with helium as the working fluid. The flow rate through the device is m = 1 kg/s. The cycle consists of four processes: 1-2: Reversible, adiabatic expansion from 300 kPa, 300 K to 100 kPa, 2-3: Reversible, isobaric heat transfer to double the specific volume (i.e., v3/v2 = 2) 3-4: Reversible, adiabatic compression back to the original pressure 4-1: Reversible, isobaric heat transfer back to the original state a) Complete the following table: State T P 1 300 K 300 kPa 2 100 kPa 3 4 300 kPa V h S 1574 kJ/kg 29.33 kJ/kg-K

A closed cycle is executed with helium as the working fluid. The flow rate through the device is m = 1 kg/s. The cycle consists of four processes: 1-2: Reversible, adiabatic expansion from 300 kPa, 300 K to 100 kPa, 2-3: Reversible, isobaric heat transfer to double the specific volume (i.e., v3/v2 = 2) 3-4: Reversible, adiabatic compression back to the original pressure 4-1: Reversible, isobaric heat transfer back to the original state a) Complete the following table: State T P 1 300 K 300 kPa 2 100 kPa 3 4 300 kPa V h S 1574 kJ/kg 29.33 kJ/kg-K

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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A closed cycle is executed with helium as the working fluid. The flow rate through the device is m in = 1 kg/s.
The cycle consists of four processes:
1→2: Reversible, adiabatic expansion 
2→3: Reversible, isobaric heat transfer to double the specific volume (i.e., v3/v2 = 2)
3→4: Reversible, adiabatic compression back to the original pressure
4→1: Reversible, isobaric heat transfer back to the original state

a) Complete the following table and mention what the physical state of helium is in each step. Assume R= 2.077 for helium and k= cp/cv= = 5.1926/3.1156 = 1.6667. Detail the assumptions for each formula we are using for each box we fill. 

b) show the states and process path on a P-v and T-s diagram. 

A closed cycle is executed with helium as the working fluid. The flow rate through the device is m = 1 kg/s. The cycle consists of four processes: 1-2: Reversible, adiabatic expansion from 300 kPa, 300 K to 100 kPa, 2-3: Reversible, isobaric heat transfer to double the specific volume (i.e., v3/v2 = 2) 3-4: Reversible, adiabatic compression back to the original pressure 4-1: Reversible, isobaric heat transfer back to the original state a) Complete the following table: State T P 1 300 K 300 kPa 2 100 kPa 3 4 300 kPa V h S 1574 kJ/kg 29.33 kJ/kg-K
Transcribed Image Text:A closed cycle is executed with helium as the working fluid. The flow rate through the device is m = 1 kg/s. The cycle consists of four processes: 1-2: Reversible, adiabatic expansion from 300 kPa, 300 K to 100 kPa, 2-3: Reversible, isobaric heat transfer to double the specific volume (i.e., v3/v2 = 2) 3-4: Reversible, adiabatic compression back to the original pressure 4-1: Reversible, isobaric heat transfer back to the original state a) Complete the following table: State T P 1 300 K 300 kPa 2 100 kPa 3 4 300 kPa V h S 1574 kJ/kg 29.33 kJ/kg-K
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