A clinical trial was conducted to test the effectiveness of a drug used for treating insomnia in older subjects. After treatment with the drug, 28 subjects had a mean wake time of 90.6min and a standard deviation of 40.2 minutes. Assume that the sample values appear to be from a normally distributed population and construct a 90% confidence interval estimate of the standard deviation of the wake times for a population with the drug treatments. Does the result indicate whether the treatment is effective?
Q: A clinical trial was conducted to test the effectiveness of a drug for treating insomnia in older…
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Q: clinical trial was conducted to test the effectiveness of a drug for treating insomnia in older…
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Q: Find the confidence interval estimate. enter your response here min<σ<enter your response here min…
A: It is given that Sample mean = 94.7Sample standard deviation = 44.2Confidence level = 95%Sample size…
Q: A clinical trial was conducted to test the effectiveness of a drug used for treating insomnia in…
A: Given That The sample size is n=16 The sample mean is X=91.6 The sample standard deviation is s=40.1…
Q: A clinical trial was conducted to test the effectiveness of a drug used for treating insomnia in…
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Q: In a test of the effectiveness of garlic for lowering cholesterol, 49 subjects were treated with…
A: Here we need to find a 95% confidence interval for the mean net change in LDL cholesterol after the…
Q: A clinical trial was conducted to test the effectiveness of a drug used for treating insomnia in…
A: The degrees of freedom is, df=n-1=23-1=22 The degrees of freedom is 22. Critical value for χU2 : The…
Q: In a test of the effectiveness of garlic for lowering cholesterol, 48 subjects were treated with…
A:
Q: In a test of the effectiveness of garlic for lowering cholesterol, 49 subjects were treated with…
A:
Q: A clinical trial was conducted to test the effectiveness of a drug for treating insomnia in older…
A: It is given that a clinical trial was conducted to test the effectiveness of a drug for treating…
Q: and after the treatment. The changes (before-after) in their levels of LDL cholesterol (in mg/dL)…
A: Given n=sample size=49, Sd=17.1, mean difference x̄d=2.8 Level of significance ɑ=0.05
Q: In a test of the effectiveness of garlic for lowering cholesterol, 47 subjects were treated with…
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Q: A clinical trial was conducted to test the effectiveness of a drug used for treating insomnia in…
A: Given : Sample Size (n) = 26 standard deviation(s) = 40.7 The level of significance (L) =0.10…
Q: A clinical trial was conducted to test the effectiveness of a drug for treating insomnia in older…
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Q: A clinical trial was conducted to test the effectiveness of a drug used for treating insomnia in…
A: From the provided information, Sample size (n) = 29 Sample mean (x̅) = 93.7 min Sample standard…
Q: nd a standard deviation of 18.9. Construct a 90% confidence interval estimate of the mean net change…
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Q: In a test of the effectiveness of garlic for lowering cholesterol, 50 subjects were treated with…
A: Given n=50 Mean=5.5 Standard deviations=17.9 Alpha=0.01
Q: A clinical trial was conducted to test the effectiveness of a drug used for treating insomnia in…
A: Given: We have Sample Size (n)=20 Sample Mean (X¯)=91.3 Sample Standard Deviation (s) =40.5 90%…
Q: A clinical trial was conducted to test the effectiveness of a drug for treating insomnia in older…
A: Assume that µ is the true mean wake time for a population with the drug treatment.
Q: A clinical trial was conducted to test the effectiveness of a drug used for treating insomnia in…
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Q: A clinical trial was conducted to test the effectiveness of a drug for treating insomnia in older…
A: The sample size is 15, sample mean is 95.5, and sample standard deviation is 21.8.
Q: drug for treating insomnia in older subjects. Before treatment, 13 subjects had a mean wake time of…
A: Given Xbar=95.3 Standard deviation=23.2
Q: A clinical trial was conducted to test the effectiveness of a drug used for treating insomnia in…
A: Introduction: The 100 (1 – α) % confidence interval for the population standard deviation, σ, is the…
Q: A clinical trial was conducted to test the effectiveness of a drug for treating insomnia in older…
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Q: A clinical trial was conducted to test the effectiveness of a drug used for treating insomnia in…
A: Given data,n=15x=91.8s=42.7α=0.10t-critical value at α=0.10 and df=14 is tc=1.761
Q: A clinical trial was conducted to test the effectiveness of a drug for treating insomnia in older…
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Q: A clinical trial was conducted to test the effectiveness of a drug used for treating insomnia in…
A: Given n=29, s=44.6=sample standard deviations Level of significance ɑ=0.10
Q: A clinical trial was conducted to test the effectiveness of a drug for treating insomnia in older…
A: given data with drug treatment n = 24 x¯ = 80.4s = 23.990% ci for mean
Q: Find the confidence interval estimate. min <a<min (Round to two decimal places as needed.)
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Q: A clinical trial was conducted to test the effectiveness of a drug for treating insomnia in older…
A: From the given information we find the confidence interval.
Q: clinical trial was conducted to test the effectiveness of a drug used for treating insomnia in older…
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Q: A clinical trial was conducted to test the effectiveness of a drug for treating insomnia in older…
A: From the given information, Sample size n =24 Sample mean, x̅=100.3. Sample standard deviation,…
Q: A clinical trial was conducted to test the effectiveness of a drug used for treating insomnia in…
A: Sample size, n=20 Sample standard deviation, s = 43.9
Q: A clinical trial was conducted to test the effectiveness of a drug for treating insomnia in older…
A: Given data: Sample size(n) = 25 Mean = 82.1 Standard deviation = 24.6 To construct 95% confidence…
Q: A clinical trial was conducted to test the effectiveness of a drug for treating insomnia in older…
A: Given: x¯=100.3n=17s=20.3c=90%=0.90
Q: A clinical trial was conducted to test the effectiveness of a drug for treating insomnia in older…
A: A confidence interval is a type of estimate computed from the statistics of the observed data. This…
Q: clinical trial was conducted to test the effectiveness of a drug used for treating insomnia in older…
A: Given n=26, x̄=95.2, s=40.7 ɑ=0.02
Q: A clinical trial was conducted to test the effectiveness of a drug used for treating insomnia in…
A: Find critical values for chi-square distribution: Refer chi-square table to find the critical…
Q: A clinical trial was conducted to test the effectiveness of a drug used for treating insomnia in…
A: Find critical values for chi-square distribution: Refer chi-square table to find the critical…
Q: In a test of the effectiveness of garlic for lowering cholesterol, 49 subjects were treated with…
A: sample size(n)=49Mean()=3.6standard deviation(s)=17.7confidence level=90%
Q: A clinical trial was conducted to test the effectiveness of a drug used for treating insomnia in…
A: Obtain the 90% confidence interval estimate of the standard deviation of the wake times for a…
Q: In a test of the effectiveness of garlic for lowering cholesterol, 49 subjects were treated with…
A:
Q: A clinical trial was conducted to test the effectiveness of a drug used for treating insomnia in…
A: A sample of 12 subjects had a mean wake time of 96.1 min and a standard deviation of 43.4 min. The…
Q: a clinical trial was conducted to test the effectiveness of a drug used for treating insomnia in…
A: The objective of this question is to construct a 95% confidence interval for the standard deviation…
Q: A clinical trial was conducted to test the effectiveness of a drug used for treating insomnia in…
A: Given that Sample size n = 21 Sample SD s = 43.5 We have to find the 90% confidence interval for…
Q: A clinical trial was conducted to test the effectiveness of a drug for treating insomnia in older…
A: Introduction: The 100 (1 – α) % confidence interval for the population mean, μ, when the population…
Q: A clinical trial was conducted to test the effectiveness of a drug for treating insomnia in older…
A: Given, After treatment, the17 subjects had a mean wake time of 96.8 min and a standard deviation of…
A clinical trial was conducted to test the effectiveness of a drug used for treating insomnia in older subjects. After treatment with the drug, 28 subjects had a mean wake time of 90.6min and a standard deviation of 40.2 minutes. Assume that the sample values appear to be from a
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- A clinical trial was conducted to test the effectiveness of a drug used for treating insomnia in older subjects. After treatment with the drug, 24 subjects had a mean wake time of 90.7 min and a standard deviation of 41.3 min. Assume that the 24 sample values appear to be from a normally distributed population and construct a 95% confidence interval estimate of the standard deviation of the wake times for a population with the drug treatments. Does the result indicate whether the treatment is effective? Find the confidence interval estimate. ___min <σ<___ minA clinical trial was conducted to test the effectiveness of a drug for treating insomnia in older subjects. Before treatment, 20 subjects had a mean wake time of 101.0 min. After treatment, the 20 subjects had a mean wake time of 97.8 min and a standard deviation of 23.1 min. Assume that the 20 sample values appear to be from a normally distributed population and construct a 90% confidence interval estimate of the mean wake time for a population with drug treatments. What does the result suggest about the mean wake time of 101.0 min before the treatment? Does the drug appear to be effective? Construct the 90% confidence interval estimate of the mean wake time for a population with the treatment. What does the result suggest about the mean wake time of 01.0min before the treatment? Does the drug appear to be effective?A clinical trial was conducted to test the effectiveness of a drug for treating insomnia in older subjects. Before treatment, 20 subjects had a mean wake time of 105.0 min. After treatment, the 20 subjects had a mean wake time of 82.5 min and a standard deviation of 22.5 min. Assume that the 20 sample values appear to be from a normally distributed population and construct a 90% confidence interval estimate of the mean wake time for a population with drug treatments. What does the result suggest about the mean wake time of 105.0 min before the treatment? Does the drug appear to be effective? Construct the 90% confidence interval estimate of the mean wake time for a population with the treatment. ???? min<μ<???? min
- A clinical trial was conducted to test the effectiveness of a drug for treating insomnia in older subjects. Before treatment, 20 subjects had a mean wake time of 101.0 min. After treatment, the 20 subjects had a mean wake time of 78.2 min and a standard deviation of 22.3 min. Assume that the 20 sample values appear to be from a normally distributed population and construct a 95% confidence interval estimate of the mean wake time for a population with drug treatments.Bone mineral density (BMD) is a measure of bone strength. Studies show that BMD declines after age 45. The impact of exercise may increase BMD. A random sample of 59 women between the ages of 41 and 45 with no major health problems were studied. The women were classified into one of two groups based upon their level of exercise activity: walking women and sedentary women. The 39 women who walked regularly had a mean BMD of 5.96 with a standard deviation of 1.22. The 20 women who are sedentary had a mean BMD of 4.41 with a standard deviation of 1.02. Which of the following inference procedures could be used to estimate the difference in the mean BMD for these two types of womenA clinical trial was conducted to test the effectiveness of a drug used for treating insomnia in older subjects. After treatment with the drug, 23 subjects had a mean wake time of 93.6 min and a standard deviation of 43.8 min. Assume that the 23 sample values appear to be from a normally distributed population and construct a 90% confidence interval estimate of the standard deviation of the wake times for a population with the drug treatments. Does the result indicate whether the treatment is effective? Find the confidence interval estimate. minA clinical trial was conducted to test the effectiveness of a drug for treating insomnia in older subjects. Before treatment, 17 subjects had a mean wake time of 103.0 min. After treatment, the 17 subjects had a mean wake time of 96.4 min and a standard deviation of 23.7 min. Assume that the 17 sample values appear to be from a normally distributed population and construct a 95% confidence interval estimate of the mean wake time for a population with drug treatments. What does the result suggest about the mean wake time of 103.0 min before the treatment? Does the drug appear to be effective? Construct the 95% confidence interval estimate of the mean wake time for a population with the treatment. min<μ< min (Round to one decimal place as needed.)A clinical trial was conducted to test the effectiveness of a drug for treating insomnia in older subjects. Before treatment, 25 subjects had a mean wake time of 102.0 min. After treatment, the 25 subjects had a mean wake time of 79.6 min and a standard deviation of 21.5 min. Assume that the 25 sample values appear to be from a normally distributed population and construct a 95% confidence interval estimate of the mean wake time for a population with drug treatments. What does the result suggest about the mean wake time of 102.0 min before the treatment? Does the drug appear to be effective? Construct the 95% confidence interval estimate of the mean wake time for a population with the treatment. __min<u<__min Round one decimal place as needed.A clinical trial was conducted to test the effectiveness of a drug for treating insomnia in older subjects. Before treatment, 18 subjects had a mean wake time of 101.0 min. After treatment, the 18 subjects had a mean wake time of 97.7 min and a standard deviation of 21.7min. Assume that the 18 sample values appear to be from a normally distributed population and construct a 90% confidence interval estimate of the mean wake time for a population with drug treatments. What does the result suggest about the mean wake time of 101.0 min before the treatment? Does the drug appear to be effective? Construct the 90% confidence interval estimate of the mean wake time for a population with the treatment. ____min<μ<___minA clinical trial was conducted to test the effectiveness of a drug used for treating insomnia in older subjects. After treatment with the drug, 20 subjects had a mean wake time of 92.5 min and a standard deviation of 43.9 min. Assume that the 20 sample values appear to be from a normally distributed population and construct a 90% confidence interval estimate of the standard deviation of the wake times for a population with the drug treatments. Does the result indicate whether the treatment is effective? Find the confidence interval estimate. minA clinical trial was conducted to test the effectiveness of a drug used for treating insomnia in older subjects. After treatment with the drug, 11 subjects had a mean wake time of 97.2 min and a standard deviation of 43.4 min. Assume that the 11 sample values appear to be from a normally distributed population and construct a 90% confidence interval estimate of the standard deviation of the wake times for a population with the drug treatments. Does the result indicate whether the treatment is effective? Find the confidence interval estimate. (answer) min less then σ less than (answer) minIn a test of the effectiveness of garlic for lowering cholesterol, 49 subjects were treated with garlic in a processed tablet form. Cholesterol levels were measured before and after the treatment. The changes (before- after) in their levels of LDL cholesterol (in mg/dL) have a mean of 3.1 and a standard deviation of 15.8. Construct a 95% confidence interval estimate of the mean net change in LDL cholesterol after the garlic treatment. What does the confidence interval suggest about the effectiveness of garlic in reducing LDL cholesterol? Click here to view a t distribution table. Click here to view page 1 of the standard normal distribution table. Click here to view page 2 of the standard normal distribution table. What is the confidence interval estimate of the population mean µ? mg/dL mg/dL<µ< (Round to two decimal places as needed.) What does the confidence interval suggest about the effectiveness of the treatment? O A. The confidence interval limits contain 0, suggesting that the…SEE MORE QUESTIONSRecommended textbooks for youA First Course in Probability (10th Edition)ProbabilityISBN:9780134753119Author:Sheldon RossPublisher:PEARSONA First Course in Probability (10th Edition)ProbabilityISBN:9780134753119Author:Sheldon RossPublisher:PEARSON