MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN: 9781119256830
Author: Amos Gilat
Publisher: John Wiley & Sons Inc
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A civil engineer has been studying the frequency of vehicle accidents on a certain stretch of interstate highway. Longterm history indicates that there has been an average of 1.76 accidents per day on this section of the interstate. Let r be a random variable that represents number of accidents per day. Let O represent the number of observed accidents per day based on local highway patrol reports. A random sample of 90 days gave the following information.

r 0 1 2 3 4 or more
O 12 24 18 20 16
A civil engineer has been studying the frequency of vehicle accidents on a certain stretch of interstate highway. Longterm history
indicates that there has been an average of 1.76 accidents per day on this section of the interstate. Let r be a random variable that
represents number of accidents per day. Let O represent the number of observed accidents per day based on local highway patrol
reports. A random sample of 90 days gave the following information.
2.
3
4 or more
12
24
18
20
16
(a) The civil engineer wants to use a Poisson distribution to represent the probability of r, the number of accidents per day.
The Poisson distribution is given below.
P(r) =
r!
Here 2 = 1.76 is the average number of accidents per day. Compute P(r) for r = 0, 1, 2, 3, and 4 or more. (Round your
answers to three decimal places.)
P(0) =
P(1) =
P(2) =
P(3) =
P(4 or more)
(b) Compute the expected number of accidents E = 90P(r) for r = 0, 1, 2, 3, and 4 or more. (Round your answers to two
decimal places.)
E(0) =
E(1) =
E(2) =
Е(3) -
E(4 or more) =
(c) Compute the sample statistic x? = E((0 - E)?/E) and the degrees of freedom. (Round your sample statistic to three
decimal places.)
df =
x? =
(d) Test the statement that the Poisson distribution fits the sample data. Use a 1% level of significance.
O Fail to reject the null hypothesis, there is sufficient evidence to conclude the Poisson distribution does not fit.
O Reject the null hypothesis, there is insufficient evidence to conclude the Poisson distribution does not fit.
Reject the null hypothesis, there is sufficient evidence to conclude the Poisson distribution does not fit.
O Fail to reject the null hypothesis, there is insufficient evidence to conclude the Poisson distribution does not fit.
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Transcribed Image Text:A civil engineer has been studying the frequency of vehicle accidents on a certain stretch of interstate highway. Longterm history indicates that there has been an average of 1.76 accidents per day on this section of the interstate. Let r be a random variable that represents number of accidents per day. Let O represent the number of observed accidents per day based on local highway patrol reports. A random sample of 90 days gave the following information. 2. 3 4 or more 12 24 18 20 16 (a) The civil engineer wants to use a Poisson distribution to represent the probability of r, the number of accidents per day. The Poisson distribution is given below. P(r) = r! Here 2 = 1.76 is the average number of accidents per day. Compute P(r) for r = 0, 1, 2, 3, and 4 or more. (Round your answers to three decimal places.) P(0) = P(1) = P(2) = P(3) = P(4 or more) (b) Compute the expected number of accidents E = 90P(r) for r = 0, 1, 2, 3, and 4 or more. (Round your answers to two decimal places.) E(0) = E(1) = E(2) = Е(3) - E(4 or more) = (c) Compute the sample statistic x? = E((0 - E)?/E) and the degrees of freedom. (Round your sample statistic to three decimal places.) df = x? = (d) Test the statement that the Poisson distribution fits the sample data. Use a 1% level of significance. O Fail to reject the null hypothesis, there is sufficient evidence to conclude the Poisson distribution does not fit. O Reject the null hypothesis, there is insufficient evidence to conclude the Poisson distribution does not fit. Reject the null hypothesis, there is sufficient evidence to conclude the Poisson distribution does not fit. O Fail to reject the null hypothesis, there is insufficient evidence to conclude the Poisson distribution does not fit.
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