A city recently launched a neighborhood watch program to control crime. The following table gives the number of crimes reported insix neighborhoods during the six months before and six months after the city launched the neighborhood watch program.Before AfterO 3.365O 3.747577349717939416528736132Let the paired difference be the number of crimes before minus the number of crimes after the city launched the neighborhood watchprogram. The null hypothesis is that the mean of the population paired differences is equal to zero (i.e., the neighborhood watchprogram does not affect the number of crimes). The alternative hypothesis is that the mean of the population paired differences isgreater than zero (i.e., the neighborhood watch program decreases the number of crimes). The significance level is 1%.What are the critical values of t for the hypothesis test?

Given table is , Before After 574173654928717379613932Also given that ,Significance level , 1% =…

Answered: A city recently launched a neighborhood…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A researcher wants to determine if the number of years of education for a parent correlates with the number of years of education for their child. The table shows the number of years of education of the parent and the number of years of education of their child for a random sample of 7. Years of Education of Parent 13 9 12 10 12 10 12 Years of Educations of their Child 15 11 10 16 17 12 17 Conduct a hypothesis test to determine if there is a significant linear correlation between the two variables. Use α = 0.05. What is the critical value for this hypothesis test? A researcher wants to determine if the number of years of education for a parent correlates with the number of years of education for their child. The table shows the number of years of education of the parent and the number of years of education of their child for a random sample of 7. Years of Education of Parent 13 9 12 10 12 10 12 Years of Educations of their Child 15 11 10 16 17 12 17…
1. Interpret the variability of the scores base from the figure. 32 34 36 38 40 42 44 46 48 50 32 34 36 38 40 42 44 46 48 50 (a) Set I (b) Set II
A statistics professor would like to build a model relating student scores on the first test to the scores on the second test. The test scores from a random sample of 21 students who have previously taken the course are given in the table. Student Test Grade 1 Test Grade 21 42 812 51 743 88 624 99 575 54 726 66 737 87 638 99 579 97 5810 89 6311 42 7712 71 6313 96 5514 56 7615 75 6916 57 7017 62 7518 89 6319 50 7220 56 7221 89 57Step 1 of 2 : Using statistical software, estimate the parameters of the modelSecond Test Grade=β0+β1(First Test Grade)+εi.Enter a negative estimate as a negative number in the regression model. Round your answers to 4 decimal places, if necessary.
The price of a share of stock divided by the company's estimated future earnings per share is called the P/E ratio. High P/E ratios usually indicate "growth" stocks, or maybe stocks that are simply overpriced. Low P/E ratios indicate "value" stocks or bargain stocks. A random sample of 51 of the largest companies in the United States gave the following P/E ratios†. 11 35 19 13 15 21 40 18 60 72 9 20 29 53 16 26 21 14 21 27 10 12 47 14 33 14 18 17 20 19 13 25 23 27 5 16 8 49 44 20 27 8 19 12 31 67 51 26 19 18 32 (a) Use a calculator with mean and sample standard deviation keys to find the sample mean x and sample standard deviation s. (Round your answers to four decimal places.) x = s = (b) Find a 90% confidence interval for the P/E population mean ? of all large U.S. companies. (Round your answers to one decimal place.) lower limit upper limit (c) Find a 99% confidence interval for the P/E population mean ? of all large U.S.…
Each of the digits in a raffle is thought to have the same chance of occurrence. The table shows the frequency of each digit for consecutive drawings in a California lottery. Perform the chi-square test to see if you reject the hypothesis at the 0.05 significance level that the digits are from a uniform population. Digit Frequency Digit Frequency 0 43 5 46 1 41 6 39 2 45 7 40 3 41 8 39 4 47 9 29 Click here for the Excel Data File a. State the decision rule. Use 0.05 significance level. (Round your answer to 3 decimal places.) H0: The digits are uniformly distributed.H1: The digits are not uniformly distributed. b. Compute the value of chi-square. (Round your answer to 3 decimal places.)
he accompanying data are x = advertising share and y = market share for a particular brand of cigarettes during 10 randomly selected years. x 0.103 0.073 0.071 0.077 0.086 0.047 0.060 0.050 0.070 0.052 y 0.132 0.126 0.122 0.086 0.079 0.076 0.065 0.059 0.051 0.039 (a) Calculate the equation of the estimated regression line. (Round your answers to six decimal places.)y = Obtain the predicted market share when the advertising share is 0.09. (Round your answer to five decimal places.)(b) Compute r2. (Round your answer to three decimal places.)(c) Calculate a point estimate of ?. (Round your answer to four decimal places.)On how many degrees of freedom is your estimate based?
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Probability. I would like to ask if how to answer these question. I really need to lean thank you!
800 700 600 500 400 300 200 100 5 10 15 20 25 30 Twenty five high school students complete a preparation program for taking the SAT test. Here are the SAT scores from the 25 students who completed the SAT prep program: 34 457 53 720 400 484 610 641 425 454514 499 64 501 625 2 471 598 509 531 The mean of these scores is 536.00. We know that the population average for SAT scores is 500 with a standard deviation of 100. Using the scatterplot above, are there any outliers?
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