A circular footing with a 1.5 m diameter is to be constructed 1.22 m below the ground surface. The subsoil consists of a uniform deposit of dense soil having the following strength parameters: Angle of Friction = 25o Nc = 24.1 Nq = 13.1 Ny = 9.1 Cohesion = 48 kN/m2 Unit weight of soil = 20.12 kN/m2 The groundwater table is at a great depth and its effect can be ignored. Determine the following: a) Ultimate bearing Capacity of the soil b) Compute the gross allowable bearing capacity of the soil using a factor of safety of 3. c) Compute the total allowable load that the footing can carry.
A circular footing with a 1.5 m diameter is to be constructed 1.22 m below the ground surface. The subsoil consists of a uniform deposit of dense soil having the following strength parameters: Angle of Friction = 25o Nc = 24.1 Nq = 13.1 Ny = 9.1 Cohesion = 48 kN/m2 Unit weight of soil = 20.12 kN/m2 The groundwater table is at a great depth and its effect can be ignored. Determine the following: a) Ultimate bearing Capacity of the soil b) Compute the gross allowable bearing capacity of the soil using a factor of safety of 3. c) Compute the total allowable load that the footing can carry.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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A circular footing with a 1.5 m diameter is to be constructed 1.22 m
below the ground surface. The subsoil consists of a uniform deposit
of dense soil having the following strength parameters:
Angle of Friction = 25o Nc = 24.1 Nq = 13.1 Ny = 9.1
Cohesion = 48 kN/m2
Unit weight of soil = 20.12 kN/m2
The groundwater table is at a great depth and its effect can be
ignored.
Determine the following:
a) Ultimate bearing Capacity of the soil
b) Compute the gross allowable bearing capacity of the soil using a
factor of safety of 3.
c) Compute the total allowable load that the footing can carry.
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