A circular disk with a radius of 0.38 m is subject to 2 tangentially applied forces. The disc is fixed such that it will rotate about its center. Both forces produce a torque in the same direction. The mass of the disc is 0.73 kg. The moment of inertia of a disc is I =1/2MR^2 F1 = 2.3 N applied at the outer edge of the disc. F2 = 3.6 N applied at a distance of 0.29 from the center of the disc. What is the angular acceleration of the disc?

Physics for Scientists and Engineers: Foundations and Connections
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Author:Katz, Debora M.
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Chapter12: Rotation I: Kinematics And Dynamics
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A circular disk with a radius of 0.38 m is subject to 2 tangentially applied forces. The disc is fixed such that it will rotate about its center. Both forces produce a torque in the same direction. The mass of the disc is 0.73 kg. The moment of inertia of a disc is I =1/2MR^2

F1 = 2.3 N applied at the outer edge of the disc.

F2 = 3.6 N applied at a distance of 0.29 from the center of the disc.

What is the angular acceleration of the disc?

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