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A chemist received a report from an analysis involving the iron-phenanthroline method, containing the calibration curve for Fe standards (20 ppm, 30 ppm, 40 ppm, 50 ppm, and 60 ppm) and their corrected absorbances. The report stated that the equation of the line and r2 were as follows: y = 0.015066 x – 0.154424 r2 = 0.9997 The sample they tested gave a corrected reading of 0.417. How much Fe is present in ppm?   2.80   17.43   2.60   37.93

A chemist received a report from an analysis involving the iron-phenanthroline method, containing the calibration curve for Fe standards (20 ppm, 30 ppm, 40 ppm, 50 ppm, and 60 ppm) and their corrected absorbances. The report stated that the equation of the line and r2 were as follows: y = 0.015066 x – 0.154424 r2 = 0.9997 The sample they tested gave a corrected reading of 0.417. How much Fe is present in ppm?   2.80   17.43   2.60   37.93

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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A chemist received a report from an analysis involving the iron-phenanthroline method, containing the calibration curve for Fe standards (20 ppm, 30 ppm, 40 ppm, 50 ppm, and 60 ppm) and their corrected absorbances. The report stated that the equation of the line and r2 were as follows:

y = 0.015066 x – 0.154424

r2 = 0.9997

The sample they tested gave a corrected reading of 0.417. How much Fe is present in ppm?

 

  1. 2.80

     

  2. 17.43

     

  3. 2.60

     

  4. 37.93

     
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