MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN: 9781119256830
Author: Amos Gilat
Publisher: John Wiley & Sons Inc
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**Step-by-Step Hypothesis Testing:**

**(b) Decision Rule for 0.05 Level of Significance:**
- **Rule:** Reject the null hypothesis if the test statistic \( t_{calc} < -2.36 \) or \( t_{calc} > 2.36 \).

**(c-1) Finding the Test Statistic \( t_{calc} \):**
- **Calculated Value:** \( t_{calc} = -0.90 \)

**(c-2) Conclusion:**
- **Decision:** We fail to reject the null hypothesis.

**Explanation:**
- The decision to reject or not reject the null hypothesis is based on the comparison of the calculated \( t \)-value against the critical values (-2.36 and 2.36). Since \( t_{calc} = -0.90 \) does not fall outside the range (-2.36, 2.36), the null hypothesis is not rejected.
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Transcribed Image Text:**Step-by-Step Hypothesis Testing:** **(b) Decision Rule for 0.05 Level of Significance:** - **Rule:** Reject the null hypothesis if the test statistic \( t_{calc} < -2.36 \) or \( t_{calc} > 2.36 \). **(c-1) Finding the Test Statistic \( t_{calc} \):** - **Calculated Value:** \( t_{calc} = -0.90 \) **(c-2) Conclusion:** - **Decision:** We fail to reject the null hypothesis. **Explanation:** - The decision to reject or not reject the null hypothesis is based on the comparison of the calculated \( t \)-value against the critical values (-2.36 and 2.36). Since \( t_{calc} = -0.90 \) does not fall outside the range (-2.36, 2.36), the null hypothesis is not rejected.
A certain company will purchase the house of any employee who is transferred out of state and will handle all details of reselling the house. The purchase price is based on two assessments, one assessor being chosen by the employee and one by the company. Based on the sample of eight assessments shown, do the two assessors agree? Use the .05 level of significance.

**Assessments of Eight Homes ($ thousands)**
```
                | Home 1 | Home 2 | Home 3 | Home 4 | Home 5 | Home 6 | Home 7 | Home 8
-----------------------------------------------------------------------------------------
Company         | 325    | 345    | 455    | 279    | 292    | 281    | 539    | 747
Employee        | 312    | 350    | 480    | 287    | 304    | 284    | 521    | 770
```
[Excel Data File Link]

### (a) Choose the appropriate hypotheses. Assume \( d = \text{company assessed value} - \text{employee assessed value} \).

- \( H_0: \mu_d = 0 \) versus \( H_1: \mu_d \neq 0 \).

- \( H_0: \mu_d \neq 0 \) versus \( H_1: \mu_d = 0 \).

### (b) State the decision rule for .05 level of significance. (Round your answers to 2 decimal places. A negative value should be indicated by a minus sign.)

Reject the null hypothesis if \( t_{calc} < -2.36 \) or \( t_{calc} > 2.36 \). ✔

### (c-1) Find the test statistic \( t_{calc} \). (Round your answer to 2 decimal places. A negative value should be indicated by a minus sign.)
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Transcribed Image Text:A certain company will purchase the house of any employee who is transferred out of state and will handle all details of reselling the house. The purchase price is based on two assessments, one assessor being chosen by the employee and one by the company. Based on the sample of eight assessments shown, do the two assessors agree? Use the .05 level of significance. **Assessments of Eight Homes ($ thousands)** ``` | Home 1 | Home 2 | Home 3 | Home 4 | Home 5 | Home 6 | Home 7 | Home 8 ----------------------------------------------------------------------------------------- Company | 325 | 345 | 455 | 279 | 292 | 281 | 539 | 747 Employee | 312 | 350 | 480 | 287 | 304 | 284 | 521 | 770 ``` [Excel Data File Link] ### (a) Choose the appropriate hypotheses. Assume \( d = \text{company assessed value} - \text{employee assessed value} \). - \( H_0: \mu_d = 0 \) versus \( H_1: \mu_d \neq 0 \). - \( H_0: \mu_d \neq 0 \) versus \( H_1: \mu_d = 0 \). ### (b) State the decision rule for .05 level of significance. (Round your answers to 2 decimal places. A negative value should be indicated by a minus sign.) Reject the null hypothesis if \( t_{calc} < -2.36 \) or \( t_{calc} > 2.36 \). ✔ ### (c-1) Find the test statistic \( t_{calc} \). (Round your answer to 2 decimal places. A negative value should be indicated by a minus sign.)
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