A cart, of mass m, is released at the top of a ramp of distance d and height h as shown. Neglect backwards friction and drag. Calculate the final speed (1vel) in each of the following cases. m [kg] h [m] d[m] vel [m/s] 0.4 1.6 2 4 2 2 4 0.4 0.80 0.4 0.80 1.6 1.6 3.20 3.20 h reference level d

805 (8 In the figure, a frictionless roller coaster car of mass m =805. kg tops the first hill with speed vo = 18.0 m/s at height h = 41.0m. What is the speed of the car at (a) point A, (b) point B, and (c) point C? (d) How high will the car go on the last hill, which is too high for it to cross? Use g=9.81 m/s?. First hill- h/2 2.

4. Here we prove a version of the work-kinetic energy theorem for an object moving in 1-D subject to a constant force. Consider a mass m, traveling initially at speed v, on which a constant net force F is applied in the same direction as its motion over a distance d. After the net force has acted over this distance, the speed of the object is v2. In terms of m, F, v1, v2, and d only, V, A) What is the acceleration of the mass? t=0 m F d t>0_m B) What is the time over which the mass travels the V, distance d? [Use one equation of constant acceleration to find this.] C) Use another equation of constant acceleration to relate m, F, v,, v2, and d. Show that the product W = Fd is equal to the change in the mass’s kinetic energy.

PRINTER VERSION 1 BACK NEX Z Your answer is partially correct. Try again. In the figure, a frictionless roller coaster car of mass m = 832 kg tops the first hill with speed vo = 19.0 m/s at height h = 44.0 m. What is the speed of the car at (a) point A, (b) point B, and (c) point C? (d) How high will the car go on the last hill, which is too high for it to cross? Use g=9.81 m/s2. First hill- B h/2 C (a) Number19 UnitsTm/s (b) Number28.15 UnitšT m/s (c) Number 35 Units m/s (d) Number" Units Click if you would like to Show Work for this question: gen/shared/assignment/test/aglist.uni?id3. Open Show Work earch 9:18 PM ENG 4/4/2021 13 ) is 16 17 .ロ/京 19home & 4 6. 7. 8. 9. 近