A car traveling at 32.0 km/h speeds up to 40.0 km/h in a time of 5.00 s. The same car later speeds up from 62.0 km/h to 70.0 km/h in a time of 5.00 s. Let the +x direction point in the direction the car is traveling. Calculate the magnitude a, of the constant acceleration for the first time interval. Determine the distance d₁ traveled by the car during the first time interval. Calculate the magnitude a2 of the constant acceleration for the second time interval. Determine the distance de traveled by the car during the second time interval. a₁ = d₁= a₂=== d₂ = m/s2 m m/s² E

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Chapter1: Units, Trigonometry. And Vectors
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A car traveling at 32.0 km/h speeds up to 40.0 km/h in a time of 5.00 s. The same car later speeds up from 62.0 km/h to
70.0 km/h in a time of 5.00 s. Let the +x direction point in the direction the car is traveling.
Calculate the magnitude a, of the constant acceleration for
the first time interval.
Determine the distance d₁ traveled by the car during the first
time interval.
Calculate the magnitude a2 of the constant acceleration for
the second time interval.
Determine the distance de traveled by the car during the
second time interval.
a₁ =
d₁ =
9₂ =
d₂ =
m/s²
m
m/s²
m
Transcribed Image Text:A car traveling at 32.0 km/h speeds up to 40.0 km/h in a time of 5.00 s. The same car later speeds up from 62.0 km/h to 70.0 km/h in a time of 5.00 s. Let the +x direction point in the direction the car is traveling. Calculate the magnitude a, of the constant acceleration for the first time interval. Determine the distance d₁ traveled by the car during the first time interval. Calculate the magnitude a2 of the constant acceleration for the second time interval. Determine the distance de traveled by the car during the second time interval. a₁ = d₁ = 9₂ = d₂ = m/s² m m/s² m
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