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![### Tire Rotation and Speed Calculation
**Problem Overview:**
A car tire has a diameter of 55.0 cm. The car is traveling at a speed of 24.0 m/s.
---
**Part A: Tire's Rotation Frequency**
**Question:**
What is the tire's rotation frequency in rpm (revolutions per minute)?
**Explanation:**
1. **Formula to Use:**
\[
\text{Rotation frequency (rpm)} = \left( \frac{\text{linear speed (m/s)}}{\text{circumference of the tire (m)}} \right) \times 60
\]
2. **Circumference Calculation:**
Given diameter = 55.0 cm = 0.55 m;
\[
\text{Circumference} = \pi \times 0.55
\]
3. **Substitute the Values:**
- Linear speed = 24.0 m/s
- Calculate and substitute to find the rotation frequency.
4. **User Response:**
- The user attempted an answer: 706 rpm.
- Feedback: Incorrect; the user has three attempts remaining.
---
**Part B: Speed at the Top Edge of the Tire**
**Question:**
What is the speed of a point at the top edge of the tire?
**Explanation:**
1. **Concept:**
- The top edge of a rotating tire moves at the speed of the car plus the speed of the tire's rotation (relative to the ground).
- Speed at the top = 2 x car speed
2. **Calculation:**
- Given car speed = 24.0 m/s
- Speed at the top = 48.0 m/s
3. **User Response:**
- The user entered: 48.0 m/s.
- Feedback: Correct.
---
This exercise requires understanding the relationship between linear speed, rotational speed, and how they relate to tire mechanics in physics.](https://content.bartleby.com/qna-images/question/b2fd9b27-3894-4c03-89ce-047a1b838456/5f05e127-b3b0-49ae-91d0-3884bd7112ca/she9ecd_processed.jpeg)
Transcribed Image Text:### Tire Rotation and Speed Calculation
**Problem Overview:**
A car tire has a diameter of 55.0 cm. The car is traveling at a speed of 24.0 m/s.
---
**Part A: Tire's Rotation Frequency**
**Question:**
What is the tire's rotation frequency in rpm (revolutions per minute)?
**Explanation:**
1. **Formula to Use:**
\[
\text{Rotation frequency (rpm)} = \left( \frac{\text{linear speed (m/s)}}{\text{circumference of the tire (m)}} \right) \times 60
\]
2. **Circumference Calculation:**
Given diameter = 55.0 cm = 0.55 m;
\[
\text{Circumference} = \pi \times 0.55
\]
3. **Substitute the Values:**
- Linear speed = 24.0 m/s
- Calculate and substitute to find the rotation frequency.
4. **User Response:**
- The user attempted an answer: 706 rpm.
- Feedback: Incorrect; the user has three attempts remaining.
---
**Part B: Speed at the Top Edge of the Tire**
**Question:**
What is the speed of a point at the top edge of the tire?
**Explanation:**
1. **Concept:**
- The top edge of a rotating tire moves at the speed of the car plus the speed of the tire's rotation (relative to the ground).
- Speed at the top = 2 x car speed
2. **Calculation:**
- Given car speed = 24.0 m/s
- Speed at the top = 48.0 m/s
3. **User Response:**
- The user entered: 48.0 m/s.
- Feedback: Correct.
---
This exercise requires understanding the relationship between linear speed, rotational speed, and how they relate to tire mechanics in physics.
![## Problem Statement
**Part C**
What is the speed of a point at the bottom edge of the tire?
Express your answer as an integer and include the appropriate units.
### Answer Submission
- Input fields for:
- **Value**
- **Units**
#### Options Available:
- Submit your answer
- Request Answer
### Additional Resources:
- [Provide Feedback]
- [Terms of Use](#)
- [Privacy Policy](#)
- [Permissions](#)
---
**Copyright © 2022 Pearson Education Inc. All rights reserved.**](https://content.bartleby.com/qna-images/question/b2fd9b27-3894-4c03-89ce-047a1b838456/5f05e127-b3b0-49ae-91d0-3884bd7112ca/7bofjc_processed.jpeg)
Transcribed Image Text:## Problem Statement
**Part C**
What is the speed of a point at the bottom edge of the tire?
Express your answer as an integer and include the appropriate units.
### Answer Submission
- Input fields for:
- **Value**
- **Units**
#### Options Available:
- Submit your answer
- Request Answer
### Additional Resources:
- [Provide Feedback]
- [Terms of Use](#)
- [Privacy Policy](#)
- [Permissions](#)
---
**Copyright © 2022 Pearson Education Inc. All rights reserved.**
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