A car initially going 68 ft/sec brakes at Q1) a constant rate (constant negative acceleration), coming to a stop in 7 seconds. Graph the velocity for t=0t=0 to t=7t=7. How far does the car travel before stopping? distance = -687 (include units) How far does the car travel before stopping if its initial velocity is doubled, but it brakes at the same constant rate? distance = 223.59 (include units)

A roly-poly bug moves on the x axis. The bug has a variable velocity which is denoted by 2 v = t² - 2.50t.t is time in seconds and v is meters per second. The origin of the roly-poly bug is at t=0. Your job is to figure out the following after 3s have passed. Be sure to use the correct amount of sig figs! a) Velocity of the bug b) The bugs acceleration c) The bugs position THIS IS How I ROLL

Which of the following statements are true regarding velocity-time graphs?I.     The slope of a velocity-time graph is acceleration.     II.    The graph has a slope of zero if the object is at rest.     III.  A line with negative slope indicates that the object is slowing down.

Please help! Required information: A cheetah can accelerate from rest to 52.9 m/s in 2.00 s. Assume that the acceleration is constant over the time interval. a) What is the magnitude of the acceleration of the cheetah? b) What is the distance traveled by the cheetah in these 2.00 s? c) A runner can accelerate from rest to 7.30 m/s in the same time, 2.00 s. What is the magnitude of the acceleration of the runner? d) A runner can accelerate from rest to 7.30 m/s in the same time, 2.00 s. By what factor is the cheetah’s average acceleration magnitude greater than that of the runner?