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A: Given : x = 36 m h = 3.05 m vo = 24 m/s θ = 45°
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A: Given: Initial speed u= 18.9 m/s upward angle θ= 41.30 Initial distance x= 49.1 m
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A: horizontal distance (d) = 36 m initial launch velocity (v) = 23.2 m/s launch angle (θ) = 49oheight…
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A: Given, Bomber altitude = 2.90 km =2900 m initial speed = 265 m/s
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A: R = u2sin2θ/g θ=43.0° R = (19.4)2sin86°/9.81 = 376.36/9.81 = 38.364m
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A: Given value--- initial speed = 18.6 m/s. angle = 49.7 degree. distance from one player to another…
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